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4 years ago

14

What is greater than 1 cup

1 answer:

77julia77 [94]4 years ago

5 0

2 cups your welcome

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Below are statements that can be used to prove that the triangles are similar. Which two statements are missing in steps 3 and 4

krek1111 [17]

Got this from a quizlet
the answers B : <B~=<Y
ABC~ZYX by the SAS similarity theorem.

8 0

3 years ago

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What is the radius of the circle whose equation is x^2 + y^2 = 8

gogolik [260]

√8

for the equations of circles: x²+y²= (radius)²

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3 years ago

2. Continuous data are usually _____________________, but discrete data are usually ______________________.

Mrrafil [7]

Answer:

Measured and Counted.

Step-by-step explanation:

Continuous data are usually “Measured”, but discrete data are usually “Counted”.

The continuous data are the data that can be measured, for example, Height of children, time in the race, length of leaf, etc. In this case, the data is taken within the range. While the discrete data is the data that can be counted. For example, the number of employees in the office, the number of students in the school, the result of rolling dice, etc. In this case, the data is a fixed number. Accordingly, the continuous data is measurable and discrete data is countable.

7 0

3 years ago

Which values are equivalent to the fraction below? 6^7/6^5

Helen [10]

Answer:

36

Step-by-step explanation:

Because the bases are the same we can just subtract the exponents to get us 6² or 36.

4 0

3 years ago

Triangle ABC has vertices at A(-2,1), B(-2,-3), and C(1,-2). What is the area of the triangle? a 18 square units b 9 square unit

natka813 [3]

Answer:

Option C. 6 square units

Step-by-step explanation:

we know that

Heron's Formula is a method for calculating the area of a triangle when you know the lengths of all three sides.

Let

a,b,c be the lengths of the sides of a triangle.

The area is given by:

$A=\sqrt{p(p-a)(p-b)(p-c)}$

where

p is half the perimeter

p= $\frac{a+b+c}{2}$

we have

Triangle ABC has vertices at A(-2,1), B(-2,-3), and C(1,-2)

the formula to calculate the distance between two points is equal to

$d=\sqrt{(y2-y1)^{2}+(x2-x1)^{2}}$

step 1

Find the distance AB

$d=\sqrt{(-3-1)^{2}+(-2+2)^{2}}$

$d=\sqrt{(-4)^{2}+(0)^{2}}$

$dAB=4\ units$

step 2

Find the distance BC

$d=\sqrt{(-2+3)^{2}+(1+2)^{2}}$

$d=\sqrt{(1)^{2}+(3)^{2}}$

$dBC=\sqrt{10}\ units$

step 3

Find the distance AC

$d=\sqrt{(-2-1)^{2}+(1+2)^{2}}$

$d=\sqrt{(-3)^{2}+(3)^{2}}$

$dBC=\sqrt{18}\ units$

step 4

$a=AB=4\ units$

$b=BC=\sqrt{10}\ units$

$c=AC=\sqrt{18}\ units$

Find the half perimeter p

p= $\frac{4+\sqrt{10}+\sqrt{18}}{2}=5.70\ units$

Find the area

$A=\sqrt{5.7(5.7-4)(5.7-3.16)(5.7-4.24)}$

$A=\sqrt{5.7(1.7)(2.54)(1.46)}$

$A=\sqrt{35.93}$

$A=6\ units^{2}$

7 0

3 years ago