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3 years ago

What is greater than 1 cup

Mathematics

1 answer:

77julia77 [94]3 years ago

5 0

2 cups your welcome

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Find the sum of 1 3/7 plus 10 6/7

kap26 [50]

Answer:

Step-by-step explanation:

3/7 + 6/7 = 9/7

Change 9/7 to a mixed number = 1 2/7

Add your whole numbers: 1 + 10 + 1 = 12

Answer: 12 2/7

7 0

2 years ago

Can someone give me a fake band name???

Ipatiy [6.2K]

Answer:

loaded diper

Step-by-step explanation:

8 0

2 years ago

Will surveyed students at his school about whether they have ever gone snowboarding and whether they own a skateboard. He found

larisa [96]

Answer:

third graph

Step-by-step explanation:

We represent the above information in a two way frequency table.

Have Snowboarded Never Snawboarded Total

Skateboard 35 64 99

No Skateboard 13 147 160

Total 48 211 259

Therefore, the third graph is the correct answer.

6 0

3 years ago

Read 2 more answers

The sum of three consecutive even numbers is 96. What is the smallest of the three numbers

lidiya [134]

The answer is 30.

First off, the numbers are consecutive even numbers. So, the difference between every consecutive number is 2 (numbers go from even to odd to even to odd...). Since the sum of their numbers is 96, I divided that by 3 to get 32. This gives me the median of the three numbers. To find the smallest number, I simply subtracted 2 from the 32.

This may help:

96/3=32

32 + 32 + 32 = 96
(32-2)+(32+0)+(32+2)=96
30+32+34=93

8 0

2 years ago

Plz..... Solve this questions for me...

faust18 [17]

$6.\\\text{We know}\ 9=3^2.\ \text{Therefore}\\\\9^2=(3^2)^2\\\\\text{use}\ (a^n)^m=a^{nm}\\\\9^2=(3^2)^2=3^{2\cdot2}=3^4\\\\\boxed{3^4=9^2}\\=================$

$7.\\METHOD\ 1:\\\\\sqrt{7^4}=\sqrt{7^{2\cdot2}}\\\\\text{use}\ (a^n)^m=a^{nm}\\\\=\sqrt{(7^2)^2}\\\\\text{use}\ \sqrt{a^2}=a\ \text{for}\ a\geq0\\\\=\boxed{7^2}\\\\METHOD\ 2:\\\\\text{use}\ a^\frac{m}{n}=\sqrt[n]{a^m}\\\\\sqrt{7^4}=7^\frac{4}{2}=\boxed{7^2}\\=================$

$8.\\5^a\times5^b=5^{11}\\\\a)\\\text{use}\ a^n\times a^m=a^{n+m}\\\\5^a\times5^b=5^{a+b}\\\\5^{a+b}=5^{11}\Rightarrow a+b=11\\\\11\ \text{is odd. The sum of even and odd is odd. Therefore}\ a\ \text{and}\ b\ \text{can't be even.}\\--------------------\\\\b)\\5\ \text{solutions}\\\\11=5+6\\11=4+7\\11=3+8\\11=2+9\\11=1+10$

3 0

2 years ago