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ser-zykov [4K]
4 years ago
14

What is greater than 1 cup

Mathematics
1 answer:
77julia77 [94]4 years ago
5 0
2 cups your welcome
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What is the height of a trapazoid with an area of 9m squared and bases that measure 2.4 m and 3.6 m
kifflom [539]
The formula of the area of a trapezoid is equal to:
Area = (a+b) / 2 * h

Substituting the values.
9 = (2.4 + 3.6) / 2 * h
9 = 6 / 2  h
9 = 3h
h = 3

So the height of the trapezoid is equal to 3m.
5 0
3 years ago
Which ordered pair is a solution of the equation 4x-2y=16?
Lisa [10]

Substitute the coordinates of points to the equation.

4x-2y=16

A.\ (-5,\ -3)\\\\4(-5)-2(-3)=16\\-20+6=16\\-14=16\ \ \ FALSE\\\\B.\ (-5,\ 3)\\\\4(-5)-2(3)=16\\-20-6=16\\-26=16\ \ \ FALSE\\\\C.\ (6,\ -4)\\\\4(6)-2(-4)=16\\24+8=16\\32=16\ \ \ \ FALSE\\\\D.\ (6,\ 4)\\\\4(6)-2(4)=16\\24-8=16\\16=16\ \ \ \ CORRECT\\\\Answer:\ \boxed{D.\ (6,\ 4)}

5 0
3 years ago
Please help whilst I try to solve this as well.
lidiya [134]

Answer:

420

Step-by-step explanation:

7 0
2 years ago
Read 2 more answers
Please need help on this one not even sure on this
zlopas [31]

Answer:

I‘m pretty sure its a special right triangle, basically a 30, 60, 90 triangle. I checked with the formula and it’s correct. So the angle W is wither a 60 Degree or 30 degree and I‘m on the side of 30 degrees.

So I’m pretty sure its 30 degree.

The formuda is the hypotenuse is 2x and the (a) (3 in this case) is x. The 5 would come out as the formula 3\sqrt{3}. Now we know the sides, 3, 5 and 6 so we just plug it in and solve for the square root and it equals to ABOUT 5.

I’m not sure if I’m correct but I’m not confident.

7 0
3 years ago
The drawing below represents a 22-foot ladder with its base placed 10 feet from the bottom of a vertical wall.
Nesterboy [21]

Answer:

63°

Step-by-step explanation:

To get the value of x we will use the Pythagoras theorem

hyp² = opp²+adj²

Given

hyp is the length of the ladder = 22ft

Adjacent is the distance from the base of the ladder to the wall = 10ft

Angle of elevation = x

Using the SOH CAH TOA identity

Cos theta = adjacent/hypotenuse

Cos x = 10/22

Cos x = 5/11

x = arccos(5/11)

x = arccos(0.4545)

x = 62.96°

Hence the best estimate of x is 63°

4 0
3 years ago
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