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xxMikexx [17]
1 year ago
11

During one month there were 7 days of precipitation. what if there had only been 3 days of precipitation that month? how would t

hat change the measures of center? if necessary, round your answers to the nearest tenth.
Mathematics
1 answer:
Marina86 [1]1 year ago
5 0

The Mean will decrease while the Median and the Mode will remain with the same amount.

For Central Measures, we have Median, Mode and  Mean. They try to describe the whole distribution by one value, in the center of it.

For this question, let's pick some examples from the Old Faithful, WY Station to the National Oceanic and Atmospheric Administration from 2015, January

1st Case Scenario:

For 7 days of precipitation, (Snow, ice pellets, etc. rain) in inches:

19 19 19 24 23 23 23 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0

Mean = 5

Median=0 (the sum of the 15th+16th position over 2)

Mode=0 (Most common observations)

2nd Case Scenario

For 3 days of precipitation, (Snow, ice pellets, etc. rain) in inches:

0 0 0 24 0 0 23 0 19 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0

Mean = 2.2

Median =0

Mode=0

Learn more about mean, median, mode here:brainly.com/question/14532771

#SPJ4

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Answer: 0.4 meters per hour.

Step-by-step explanation:

The rate of change of distance with respect to time is known as speed.

Formula :\text{Rate of change}=\dfrac{\text{Change in position}}{\text{Change in time}}

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i.e. \text{Rate of change}=\dfrac{0.8}{2}=0.4

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Step-by-step explanation:

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