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2 years ago

Joe and Sue were trying to calculate the square inches of paper needed to create a cone for the cotton candy. The radius

1 answer:

7 0

The correct statements are Neither was correct and Joe used the height and radius to calculate the slant height.

<h3>How to find the square inches of paper needed.</h3>

The square inches of paper needed A = surface area of cone + area of overlap

<h3>Surface area of cone</h3>

The surface area of the cone is given by A = πr[r + √(h² + r²)] where

r = radius of cone = 2 in and
h = height of cone = 6 in.

So, A = πr[r + √(h² + r²)]

A = π × 2 × [2 + √(6² + 2²)]

A = π × 2 × [2 + √(36 + 4)]

A = π × 2 × [2 + √40]

A = π × 2 × [2 + 2√10]

A = 2π[2 + 2√10]

A = 4π + 4π√10

<h3>The area of overlap</h3>

The area of overlap A' = wL where

w = width of overlap = 1/2 in and
L = slant height of cone = √(h² + r²)

So, A' = wL

A' = w[√(h² + r²)]

A' = 1/2[√(6² + 2²)]

A' = 1/2[√(36 + 4)]

A' = 1/2[√40]

A' = 1/2 × 2√10

A' = √10

So, the number of square inches of paper needed is A" = A + A'

= 4π + 8π√10 + √10

Since the number of square inches of paper needed is 4π + 4π√10 + √10

So, the correct statements are Neither was correct and Joe used the height and radius to calculate the slant height.

Learn more about surface area of cone here:

brainly.com/question/24979679

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Gala2k [10]

Answer:

oh lord...ill try my best

Step-by-step explanation:

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a.) When we reflect over xz plane x and z coordinates stay same, y coordinate changes to same numerical value but opposite sign. Moving front-back is moving over x-axis, moving left-right is moving over y-axis, moving up-down is moving over z-axis.

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3 years ago

If a plane can climb at 2,400 feet per minute, how many minutes are needed to climb to 60,000 feet?

cestrela7 [59]

Hi there --

If a plane can climb 2,400 feet per minute, it will need 25 minutes to reach 60,000 feet. // By dividing 60,000 (the needed feet) by 2,400 (the amount of feet the plane can climb per/min) you get 25 (the amount of mins needed to climb 60,000 feet)

Hope this helps! Have a great day! :)

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3 years ago

Joe can cut and split a cord of firewood in 3 fewer hours than Dwight can. When they work together, it takes them 2 hours. How

aalyn [17]

Answer:

Dwight will take 6 hours to finish the job alone and Joe will take 3 hours to finish the job alone.

Step-by-step explanation:

Let us assume the time taken by Dwight to split a cord of firewood = K hrs

So, the per hour rate of Dwight = $(\frac{1}{K})$

As, Joe uses 3 LESS hours then Dwight.

So, the time taken by Joe to split a cord of firewood = (K- 3) hrs

So, the per hour rate of Joe = $(\frac{1}{K-3})$

Now, when both of them wok together, it takes them 2 hours.

So, the per hour rate of BOTH of them = $(\frac{1}{2})$

⇒ Per hour rate of ( Dwight + Joe) = $(\frac{1}{2} )$

$\implies (\frac{1}{K}) + (\frac{1}{K-3}) = (\frac{1}{2})$

Now, solving for the value of K , we get:

$(\frac{1}{K}) + (\frac{1}{K-3}) = (\frac{1}{2})\\\implies \frac{(K-3) + K}{K (K-3)} = (\frac{1}{2})\\\implies 2(2K -3) = K^2 - 3K\\\implies k^2 - 3K -4K +6 = 0\\\implies K^2 - 7K + 6= 0\\\implies K^2 - 6K - K + 6= 0\\\implies K(K-6) -1(K - 6)= 0\\\implies (K-6)(K-1) = 0$

Implies either K = 6 Or K = 1

But if K = 1, (K-3) = 1- 3 = -2 hours would be A CONTRADICTION.

⇒ K = 6 hours

Hence, Dwight will take 6 hours to finish the job alone and Joe will take (k-3) = (6-3) = 3 hours to finish the job alone.

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Check out the attached image below for the illustration of the triangle.

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