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kifflom [539]
2 years ago
8

What is the range of f? ​

Mathematics
1 answer:
Andrew [12]2 years ago
7 0

Answer:

[-4,5]

Step-by-step explanation:

you look on the starting point and the ending point of the y-axis ( you always start with the smallest value)

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using the midpoint formula, solve for the midpoint of the segment with these pairs of endpoints (-11,30) and (-26,-2)​
REY [17]

Answer:

Midpoint is (\frac{-37 }{2},  14)

Step-by-step explanation:

Midpoint = (\frac{x_{1} + x_{2} }{2}, \frac{y_{1} + y_{2} }{2})

              = (\frac{-11 -26}{2}, \frac{30 - 2 }{2})

              =  (\frac{-37 }{2}, \frac{28 }{2})

              =  (\frac{-37 }{2},  14)

Midpoint is (-37/2, 14)

3 0
3 years ago
H + 1/3 when h= 1 2/3
Bess [88]
2. Because if 1/3 + 2/3 is 1 then 1+1=2
8 0
3 years ago
Read 2 more answers
A homeowner has an octagonal gazebo inside a circular area. Each vertex of the gazebo lies on the circumference of the circular
Tcecarenko [31]

If we draw the diagonals of the octagonal gazebo, the 4 diagonals divide the octagon into 8 triangles.

Note that each triangle is an isosceles triangle whose equal sides are x, the radius of the circle.

The top angle of each triangle is obtained by dividing the full angle by 8.

So, each top angle = \frac{360}{8}

= 45°

Now, in fig., consider one of the triangles Δ OAB. Draw an altitude OC from O to the opposite side AB.

This altitude OC bisects the top angle 45°.

Therefore, ∠ AOC = 22.5°.

Now, in Δ AOC,

sin 22.5=\frac{AC}{OA}

=\frac{AC}{x}

So, AC = x sin 22.5°

Note that, AB = 2 AC.

Therefore, AB = 2x sin 22.5°.

Also, cos 22.5=\frac{OC}{OA}

=\frac{OC}{x}

So, OC = x cos 22.5°.

Area of Δ AOB = \frac{1}{2}(AB)(OC)

= \frac{1}{2} × (2x sin 22.5°) × (x cos 22.5°)

= \frac{1}{2} x^{2} (2 sin 22.5° cos 22.5°)

= \frac{1}{2} x^{2} sin 45°

= x^{2} / 2\sqrt{2}

Area of the octagonal gazebo = 8 × one triangular area

= 8 × (x^{2} / 2\sqrt{2})

=2\sqrt{2} x^{2}

=2.828x^{2}

Area required for mulch = circular area - area of the gazebo

=3.14x^{2} -2.828x^{2}

=0.312x^{2}

Now, cost per unit area = $1.50.

Hence, total cost g(m) = area × cost per unit area

Total cost g(m) = 0.312x^{2} × 1.5

=0.468x^{2}

Hence, total cost g(m) = 0.468x^{2}.

4 0
3 years ago
if Ingles 2 and 14 are congruent then line T and then you are parallel what is the theorem to this question ​
Nostrana [21]

Answer:

lol na im good

Step-by-step explanation:

7 0
3 years ago
The point (a,b) is in Quadrant IV of a coordinate plane. Describe the location of the point with the coordinates of (b,a)
julia-pushkina [17]

If the point (a, b) is in Quadrant IV of a coordinate plane, then the x-coordinate of (a, b) will be positive and the y-coordinate will be negative.


EX: (5, -5)


4 0
2 years ago
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