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sesenic [268]
3 years ago
12

Pls help due at 11:59

Mathematics
1 answer:
vampirchik [111]3 years ago
8 0
Angle V is 41 degrees

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Can help me how<br>Macam mana... ​
Alborosie

Step-by-step explanation:

i)

2(x+2)=7

2x+4=7

2x=7-4

2x=3

x=3/2

ii)3x + y =8 , y=x

3x + x = 8

4x = 8

x = 2

8 0
3 years ago
Read 2 more answers
What is the area of this figure. <br><br><br> 128 in<br> 136 in<br> 153 in<br> 258 in
aliya0001 [1]
So, to find the solution to this problem, we will we using pretty much the same method we used in your previous question. First, let's find the area of the rectangle. The area of a rectangle is length x width. The length in this problem is 16 and the width is 3, and after multiplying these together, we have found 48 in^2 to be the area of the square. Next, we can find the area of the trapezoid. The area of a trapezoid is ((a+b)/2)h where a is the first base, b is the second base, and h is the height. In this problem, a=16, b=5, and h=10. So, all we have to do is plug these values into the area formula. ((16+5)/2)10 = (21/2)10 = 105. So, the area of the trapezoid is 105 in^2. Now after adding the two areas together (48in^2 and 105in^2), we have found the solution to be 153in^2. I hope this helped! :)
6 0
3 years ago
Erica must tutor a minimum of 20 hours per week in order to remain in the national honor society. She has a student that she tut
irinina [24]

Answer:

3 hours every weekday

Step-by-step explanation:

20 - 5 is 15 so she must work 15 hours during the week since saturday and sunday are taken. 15 divided by 5 is 3 therefore, giving you three hours a day; Monday, Tuesday, Wednesday, Thursday, and Friday

8 0
4 years ago
The first tern of an arithmetic sequence is -3 and the fifteenth term id 53. What is the common difference of the sequence?
arsen [322]
The common difference is 4. U know that the formula is the first term + d(n -1). N-1 is 14 so u know that 14 times a number needs to equal 56 because the first term is -3 and 56-3 is 53. 14 * 4 is 56. So the common difference is 4
5 0
3 years ago
What is the sequence of transformations that maps △ABC to △A′B′C′ ? Select from the drop-down menus to correctly identify each s
torisob [31]
<h3>Answer:</h3>

Any 1 of the following transformations will work. There are others that are also possible.

  • translation up 4 units, followed by rotation CCW by 90°.
  • rotation CCW by 90°, followed by translation left 4 units.
  • rotation CCW 90° about the center (-2, -2).
<h3>Step-by-step explanation:</h3>

The order of vertices ABC is clockwise, as is the order of vertices A'B'C'. Thus, if reflection is involved, there are two (or some other even number of) reflections.

The orientation of line CA is to the east. The orientation of line C'A' is to the north, so the figure has been rotated 90° CCW. In general, such rotation can be accomplished by a single transformation about a suitably chosen center. Here, we're told there is <em>a sequence of transformations</em> involved, so a single rotation is probably not of interest.

If we rotate the figure 90° CCW, we find it ends up 4 units east of the final position. So, one possible transformation is 90° CCW + translation left 4 units.

If we rotate the final figure 90° CW, we find it ends up 4 units north of the starting position. So, another possible transformation is translation up 4 units + rotation 90° CCW.

Of course, rotation 90° CCW in either case is the same as rotation 270° CW.

_____

We have described transformations that will work. What we don't know is what is in your drop-down menu lists. There are many other transformations that will also work, so guessing the one you have available is difficult.

5 0
3 years ago
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