Angle of elevation is 37°
<u>Step-by-step explanation:</u>
As we have the opposite side 75 ft to the angle and the hypotenuse 125 ft, we can find the sine value as,
sin θ = opp/ hyp
= 75/125
= 0.6
θ = sin⁻¹ (0.6) = 36.9°≈ 37°
So angle of elevation is 37°.
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The given inequality holds for the open interval (2.97,3.03)
It is given that
f(x)=6x+7
cL=25
c=3
ε=0.18
We have,
|f(x)−L| = |6x+7−25|
= |6x−18|
= |6(x−3)|
= 6|x−3|
Now,
6|x−3| <0.18 then |x−3|<0.03 ----->−0.03<x-3<0.03---->2.97<x<3.03
the given inequality holds for the open interval (2.97,3.03)
For more information on inequality click on the link below:
brainly.com/question/11613554
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Although part of your question is missing, you might be referring to this full question: For the given function f(x) and values of L,c, and ϵ0, find the largest open interval about c on which the inequality |f(x)−L|<ϵ holds. Then determine the largest value for δ>0 such that 0<|x−c|<δ→|f(x)−|<ϵ.
f(x)=6x+7,L=25,c=3,ϵ=0.18
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