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2 years ago

I need help please !!!!!

Mathematics

2 answers:

sergey [27]2 years ago

7 0

Answer:

Vertical Angles are Congruent

Step-by-step explanation:

Angle BCA and angle DCE are congruent since they are vertical angles. Lines BE and AD cross each other to make vertical angles. You can't really know if BC equals EC for sure, as well as how Alternate Interior Angles are Congruent. I don't know how else I can explain this, but I hoped it helped you understand why it is A = Vertical Angles are Congruent.

Tems11 [23]2 years ago

5 0

Answer:

i just need the money'

Step-by-step explanation:

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The floor plan of a room has a scale of 2.5 in. : 35 ft. In the drawing, the length of the room is 8 in. and the width of the ro

Oksi-84 [34.3K]

Well if I did my math correctly I do believe the perimeter should be 392 ft.

6÷2.5= 2.4
2.4×35=84

8÷2.5= 3.2
3.2×35=112

84×2
112×2
_____
392

you mult. by 2 because it's a room which usually has four walls and I imagined it being a rectangle.

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3 years ago

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Mary was asked to find the slope of the line 3x - 4y = 12. She says the answer is 3/4

Vinvika [58]

The correct answer is D. Choose two points on the graph and count the rise and the run between them. Graph D is the only one that also has a slope of 3/4 .

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3 years ago

The table shown below shows some values for functions f(x) and g(x). What is/are the solution(s) to f(x)=g(x)? Explain your answ

salantis [7]

Answer:

x = -1

Step-by-step explanation:

Both tables show a function value of 9 for x = -1.

x = -1 is the solution to f(x) = g(x), since f(-1) = 9 = g(-1).

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3 years ago

B. Determine the values of a and b so that f is continuous.<br><br> Please help!

wlad13 [49]

Answer:

following are the solution to this question:

Step-by-step explanation:

Please find the complete question in the attached file.

$\lim_{x\to 2}+f(x) = \lim_{x\to 2}+ (ax^2-bx+3) = 4a-2b+3\\\\ \to 4a-2b+3 = 4\\\\ \therefore \ \ 4a-2b = 1\\\\$

The one-sided limits of F(x) at x = 3 must be equivalent for f(x) to be continuous at x = 3.

$\to \lim_{x\to 3}- f(x) = \lim_{x\to 3}- (ax^2-bx+3) = 9a-3b+3\\\\ \to \lim_{x\to 3}+ f(x) = \lim_{x\to 3}+ (2x-a+b) = 6-a+b\\\\$

So,

$\to 9a-3b+3 = 6-a+b\\\\\therefore\\ \to 10a -4b = 3$

$\to 4a - 2b = 1......(a)\\\to 10a - 4b = 3.......(b)\\$

In equation a multiply the by -2 and then add in the equation b:

$\to -8a + 4b = -2\\\to 10a - 4b = 3\\ \to 2a = 1\\\\ \to a = \frac{1}{2}\\\\ \to \ 4(\frac{1}{2}) - 2b = 1\\\\ \to 2 - 2b = 1\\\\ \to -2b = -1\\\\ \to b = \frac{1}{2}$

So, the value of $a \ and \ b= \frac{1}{2}$

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3 years ago

please tell me how do I answer questions. I repeat I need to know how to answer the questions? tell me please

SVEN [57.7K]

Answer:

So there is an answer button, and there is a + sign. Once you click on it, you will be able to answer questions.

Step-by-step explanation:

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2 years ago

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