Using the z-distribution, considering the standard 95% confidence level, the margin of error is of 0.0486 = 4.86%.
<h3>What is a confidence interval of proportions?</h3>
A confidence interval of proportions is given by:

The margin of error is:

In which:
is the sample proportion.
In this problem, we have a 95% confidence level, hence
, z is the value of Z that has a p-value of
, so the critical value is z = 1.96.
The sample size and the estimate are given by:

Hence the margin of error is:


M = 0.0486 = 4.86%.
More can be learned about the z-distribution at brainly.com/question/25890103
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