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1 year ago

What is the ratio between 40,000 and 200?

Mathematics

1 answer:

ziro4ka [17]1 year ago

4 0

The ratio between 40,000 and 200 is 200 : 1

<h3>How to determine the ratio?</h3>

The numbers are given as:

40,000 and 200

Express as ratio

Ratio = 40000 : 200

Divide each number by 200

Ratio = 200 : 1

Hence, the ratio between 40,000 and 200 is 200 : 1

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Multiply. Express your answer in simplest form. 11 1/9 × 4 2/7

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Answer:

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Step-by-step explanation:

Given

11 1/9 x 4 2/7

First change the fractions to improper fractions.

We have ,

100/9 x 30/7

Multiply through

3000/63

Divide the numerator and denominator by 3

1000/21

47 13/21

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3 years ago

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Please help!! dont answer if you're not going to explain! need help with my geometry!

FinnZ [79.3K]

Step-by-step explanation:

Statement:

2-) ∠BAC = ∠EDC

<em>Reason:</em>

Angles opposite to equal sides of a triangle are equal (Alternate Interior Angles Theorem)

Statement:

3-) AC = CD

<em>Reason:</em>

CPCTC ("Corresponding Parts of Congruent Triangles are Congruent")

Statement:

4-) ∠BCA = ∠DCE

<em>Reason:</em>

Vertical Angles Theorem (states that vertical angles, angles that are opposite each other and formed by two intersecting straight lines, are congruent)

Statement:

5-) triangle ABC = triangle DEC

ASA Postulate

The ASA (Angle-Side-Angle) postulate states that if two angles and the included side of one triangle are congruent to two angles and the included side of another triangle, then the triangles are congruent. (The included side is the side between the vertices of the two angles.)

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3 years ago

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MatroZZZ [7]

Answer:

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Step-by-step explanation:

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3 years ago

10. A manufacturer wanted to know if more coupons would be redeemed if they were mailed to the

Mandarinka [93]

Using the t-distribution, it is found that the data does not provide convincing evidence that the mean number is greater when the coupons were addressed to a female.

<h3>What are the hypothesis tested?</h3>

At the null hypothesis, it is tested if there is no difference, that is, the mean is of 0, hence:

$H_0: \mu = 0$

At the alternative hypothesis, it is tested if the mean number is greater for females, that is, the mean is greater than 0, hence:

$H_1: \mu > 0$

<h3>What is the test statistic?</h3>

The test statistic is given by:

$t = \frac{\overline{x} - \mu}{\frac{s}{\sqrt{n}}}$

The parameters are:

$\overline{x}$ is the sample mean.

$\mu$ is the value tested at the null hypothesis.

s is the standard deviation of the sample.

n is the sample size.

In this problem, the parameters are given as follows:

$\overline{x} = 1.5, \mu = 0, s = 4.75, n = 50$ .

Hence, the test statistic is given by:

$t = \frac{\overline{x} - \mu}{\frac{s}{\sqrt{n}}}$

$t = \frac{1.5 - 0}{\frac{4.75}{\sqrt{50}}}$

t = 2.23

<h3>What is the conclusion?</h3>

Considering a <em>right-tailed test</em>, as we are testing if the mean is greater than a value, with a <em>significance level of 0.01 and 50 - 1 = 49 df</em>, the critical value is given by $t^{\ast} = 2.4$ .

Since the test statistic is less than the critical value for the right-tailed test, the data does not provide convincing evidence that the mean number is greater when the coupons were addressed to a female.

More can be learned about the t-distribution at brainly.com/question/26454209

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3 years ago

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