Answer: 3.751*10^18kg
Step-by-step explanation:
δ =619.09−0.000097p....equa1 where p (the distance from the center of the earth) is measured in meters and δ is measured in kilograms per cubic meter.
Calculating the density of air at 5km above earth surface
P = 5000m + 6370000m = 6.375*10^6m
δ = 619.09 -(.000097* 6.375*10^6)
δ = 0.715kg/m^3 = density
Since Mass = density*volume...equ2
To calculate volume of air around the spherical earth at height 5km
V = (4/3 pai R^3) - (4/3pai r^3) ...equation 3 where R =6.375*10^6m, r = 6.37*10^6
Substituting R and r in equation 2 to solve for volume of air
V = 1.085*10^21 - 1.08*10^21
V = 5.25*10^18m^3
Substituting δ and V into equation 2 to solve for mass of air
M = 0.715 * (5.25*10^18)
M = 3.751*10^18kg
Combine like terms first:
0.5x+12x=12.5x
12.5x=5
5/12.5 is the answer
Rule of thumb in basic rounding is 5 above round up, below five don’t round up.
To round to the nearest thousand, you look at the hundred place. What is the number nearest to?
71,903 Is rounded up to 72,000
^
25,368 is rounded to 25,000
^
72,000 - 25,000 = 47,000
9514 1404 393
Answer:
-5/2
Step-by-step explanation:
The average rate of change is the slope of the line between the two points. You can see from the graph that the slope is ...
slope = rise/run = -5/2
The average rate of change on the interval is -5/2.
Answer:
The common difference is -4/3.
Step-by-step explanation:
Recall that the direct formula for an arithmetic sequence is given by:
Where <em>n</em> is the <em>n</em>th term, <em>a</em> is the initial term, and <em>d</em> is the common difference.
We are given that the first term <em>a</em> is 31.
We also know that the 28th term is -5. Hence, <em>x</em>₂₈ = -5. Substitute:
Solve for <em>d</em>. Simplify:
Thus:
Divide both sides by 27. Hence, the common difference is:
