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aleksklad [387]
3 years ago
13

I need help on dependent and independent events

Mathematics
1 answer:
strojnjashka [21]3 years ago
7 0
In other words, the event<span> has no effect on the probability of another </span>event<span> occurring. </span>Independent events<span> in probability are no different from </span>independent events<span> in real life. ... When two </span>events<span> are </span>independent<span>, one </span>event does not influence the probability of another event<span>.</span>
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A couple took out a $5,000 loan from the bank. The loan had a simple interest rate of 7.5% per year. By the end of the loan, the
Sholpan [36]

Answer:

6 years

Step-by-step explanation:

t=2250/375

t=6

Hence time of the loan will be 6 years

8 0
2 years ago
Read 2 more answers
29. 83 – 2 · 4 = <br> 30. 3 · 6 – 4 · 2 = <br> 31. 3( 6 – 4) · 2 =
tester [92]

1) 21.83

2)173.8

3)12

Hope this helps :)

4 0
3 years ago
You have been asked to build a scale model of your school out of toothpicks. imagine your school is 30 feet tall. your scale is
sveticcg [70]
Since your scale is 1ft:1.26cm, a 30-ft tall school would need to have a 30*1.26=37.8 cm model. Dividing this by how tall each toothpick is, you'll get:

\frac{37.8}{6.3} =6

ANSWER: The model would be 6 toothpicks tall.

To find out how many cotton swabs you'll need, we just divide 37.8 by how tall each swab is:

\frac{37.8}{7.7} =5

ANSWER: The model would be 5 cotton swabs tall.
4 0
3 years ago
Trucks in a delivery fleet travel a mean of 110 miles per day with a standard deviation of 38 miles per day. The mileage per day
Montano1993 [528]

Answer: 0.1824

Step-by-step explanation:

Given : The mileage per day is distributed normally with

Mean : \mu=110\text{ miles per day}

Standard deviation :  \sigma=38\text{ miles per day}

Let X be the random variable that represents the distance traveled by truck in one day .

Now, calculate the z-score :-

z=\dfrac{x-\mu}{\sigma}

For x= 132 miles per day.

z=\dfrac{132-110}{38}\approx0.58

For x= 159 miles per day.

z=\dfrac{159-110}{38}\approx1.29

Now by using standard normal distribution table, the  probability that a truck drives between 132 and 159 miles in a day will be :-

P(132

Hence, the probability that a truck drives between 132 and 159 miles in a day =0.1824

6 0
3 years ago
Given the function f(x)=3x+5a / x^2-a^2 find the value of a for which f'(12) = 0
maria [59]
The function, as presented here, is ambiguous in terms of what's being deivded by what.  For the sake of example, I will assume that you meant

           3x+5a
<span> f(x)= ------------
</span>          x^2-a^2

You are saying that the derivative of this function is 0 when x=12.  Let's differentiate f(x) with respect to x and then let x = 12:

             (x^2-a^2)(3) -(3x+5a)(2x)
f '(x) = ------------------------------------- = 0 when x = 12
                [x^2-a^2]^2

(144-a^2)(3) - (36+5a)(24)
------------------------------------  =  0
               [   ]^2

Simplifying,

(144-a^2) - 8(36+5a) = 0

144 - a^2 - 288 - 40a = 0

This can be rewritten as a quadratic in standard form:

-a^2 - 40a - 144 = 0, or a^2 + 40a + 144 = 0.

Solve for a by completing the square:

a^2 + 40a + 20^2 - 20^2 + 144 = 0
        (a+20)^2    = 400 - 144 = 156

        Then a+20 = sqrt[6(26)] = sqrt[6(2)(13)] = 4(3)(13)= 2sqrt(39)

         Finally, a = -20 plus or minus 2sqrt(39)

You must check both answers by subst. into the original equation.  Only if the result(s) is(are) true is your solution (value of a) correct.
6 0
3 years ago
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