So using a(2)=0 we can first solve for k by substituting t for 2
0 = (2-k)(2-3)(2-6)(2+3)
0 = (2-k)(-1)(-4)(5)
0 = (2-k)20
0 = 40 - 20k
-40 = -20k
k = 2
The next step would be to find all the 0s of a.
0 = (t-2)(t-3)(t-6)(t+3)
T = 2,3,6,-3
Then we find the product
2x3x6x-3 = -108
Since the problem asks for the absolute value, the answer is positive 108
Answer:
For example, the U.S. Census Bureau defines a family in the following manner: "A family is a group of two people or more (one of whom is the householder) related by birth, marriage, or adoption and residing together."
Explanation:
The species of butterfly that is shown is; Papilio polyxenes.
<h3>What are the species of butterflies?</h3>
Butterflies usually are identified by the colors and patterns shown on their wings. However, for us to identify an organism using a dichotomous key, we must compare the traits of the organism to the first pair of descriptive statements on the key as follows;
1) A swallowtail butterfly is either classified as Papilio glaucus ( where the wings are mainly yellow) or Papilio polyxenes(where the wings are mainly black)
Now, the image of the butterfly given shows that the wings are mainly black, and as a result, we will say that the butterfly specie is called Papilio Polyxenes.
Read more about species of butterflies at; brainly.com/question/16678828
The tension on each segment of the clothesline is : 110 N
<u>Given data : </u>
mass of object = 100 n = 10 kg
Horizontal distance of clothesline = 4 m
middle of clothesline sag s by : 1m
<h3 /><h3>Determine the tension on each segment of clothesline</h3>
<u>First step</u> : calculate the horizontal angle made by the sagging
β = arctan ( 1 m / 2m ) ----- ( 1 )
= arctan ( 0.5 )
≈ 26.57°
Note : Tension in th y axis ( Ty ) = Tsinβ
Therefore :
Tension on each segment can be calculated using the formula below
2Tsinβ - mg = 0
solve for T
T = mg / 2sinβ
= ( 10 * 9.8 ) / 2 * sin 26.57°
= 98 / 0.89
= 110 N
Hence we can conclude that the tension on each segment of the clothesline is : 110 N
Learn more about Tension calculations : brainly.com/question/24994188