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2 years ago

Which describes the law of conservation of matter?

Chemistry

1 answer:

Snowcat [4.5K]2 years ago

8 0

Answer:

answer is B

mark me brainliest

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Which statement describes the energy changes that occur as bonds are broken and formed during a chemical reaction? 1.Energy is a

Snowcat [4.5K]

Answer:

Explanation:

Br + Br-> Br2 (covalent bond)

bond formation releases energy, as the Br's are in a lower energy state like Br2

6 0

3 years ago

At 9°C a gas has a volume of 6.17 L. What is its volume when the gas is at standard temperature?

Alex17521 [72]

Answer:

V₂ = 5.97 L

Explanation:

Given data:

Initial temperature = 9°C (9+273 = 282 K)

Initial volume of gas = 6.17 L

Final volume of gas = ?

Final temperature = standard = 273 K

Solution:

Formula:

The Charles Law will be apply to solve the given problem.

According to this law, 'the volume of given amount of a gas is directly proportional to its temperature at constant number of moles and pressure'

Mathematical expression:

V₁/T₁ = V₂/T₂

V₁ = Initial volume

T₁ = Initial temperature

V₂ = Final volume

T₂ = Final temperature

Now we will put the values in formula.

V₁/T₁ = V₂/T₂

V₂ = V₁T₂/T₁

V₂ = 6.17 L × 273K / 282 k

V₂ = 1684.41 L.K / 282 K

V₂ = 5.97 L

5 0

3 years ago

(GIVING BRAINLIEST!!!)What is the correct formula for the ionic compound that forms when oppositely- charged ions of magnesium a

allochka39001 [22]

Pretty confident that MgO is the answer

6 0

3 years ago

Is trimming a bush because it grows too tall a chemical or physical change

professor190 [17]

Answer:

Physical Change

Explanation:

The bush is changing shapes, not changing what it is.

8 0

4 years ago

Sulfur and oxygen form both sulfur dioxide and sulfur trioxide. When samples of these were decomposed the sulfur dioxide produce

Zinaida [17]

Answer : The mass of oxygen per gram of sulfur for sulfur dioxide and sulfur trioxide is, 0.997 g and 1.5 g respectively.

Explanation : Given,

Mass of oxygen in sulfur dioxide = 3.49 g

Mass of sulfur in sulfur dioxide = 3.50 g

Mass of oxygen in sulfur trioxide = 9.00 g

Mass of sulfur in sulfur trioxide = 6.00 g

Now we have to calculate the mass of oxygen per gram of sulfur for sulfur dioxide and sulfur trioxide.

Mass of oxygen per gram of sulfur for sulfur dioxide = $\frac{\text{Mass of oxygen}}{\text{Mass of sulfur}}$

Mass of oxygen per gram of sulfur for sulfur dioxide = $\frac{3.49}{3.50}=0.997g$

and,

Mass of oxygen per gram of sulfur for sulfur trioxide = $\frac{\text{Mass of oxygen}}{\text{Mass of sulfur}}$

Mass of oxygen per gram of sulfur for sulfur trioxide = $\frac{9.00}{6.00}=1.5g$

Thus, the mass of oxygen per gram of sulfur for sulfur dioxide and sulfur trioxide is, 0.997 g and 1.5 g respectively.

8 0

3 years ago