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Bond [772]
3 years ago
11

Some of the chemicals in tobacco products cause cancer. these products are called

Chemistry
1 answer:
sergij07 [2.7K]3 years ago
6 0
Carcinogens if i am not wrong
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Exercise A mixture of 250 mL of methane, CH4, at 35 °C and 0.55 atm and 750 mL of propane, C3Hg, at 35° C and 1.5 atm, were intr
dalvyx [7]

Explanation:

The given data is as follows.

      V_{1} = 250 mL,     V_{2} = 750 mL

      T_{1} = 35^{o}C = 35 + 273 K = 308 K

      T_{2} = 35 + 273 K = 308 K

      P_{1} = 0.55 atm,    P_{2} = 1.5 atm

               P = ? ,         V = 10.0 L

Since, temperature is constant.

So,    P_{1}V_{1} + P_{2}V_{2} = PV

Now, putting the given values into the above formula as follows.

         P_{1}V_{1} + P_{2}V_{2} = PV

         0.55 atm \times 250 mL + 1.5 atm \times 1.5 atm = P \times 10.0 L

                     P = 0.126 atm

As, 1 atm = 760 torr. So, 0.126 atm \times \frac{760 torr}{1 atm} = 95.76 torr.

Thus, we can conclude that the final pressure, in torr, of the mixture is 95.76 torr.

8 0
3 years ago
1. the purpose of the aqueous solutions in a galvanic cell is to?
ludmilkaskok [199]

Answer:

1. The correct option is;

c. maintains charge balance in the cell

2. The correct option is;

c. +3.272 V

Explanation:

The aqueous solution in a galvanic cell is the electrolyte which is a ionic solution containing that permits the transfer of ions between the separated compartment of the galvanic cell such that the overall system is electrically neutral

Therefore, the aqueous solution maintains the charge balance in the cell

2. Here we have;

B₂ + 2e⁻ → 2B⁻ Ecell = 0.662 V

A⁺ + 1e⁻ → A Ecell = -1.305 V

Hence for the overall reaction, we have;

2A + B₂ → 2AB gives;

(0.662) - 2×(-1.305)  = +3.272 V.

4 0
3 years ago
How does viscosity affect boiling point?
sveticcg [70]
D- viscosity has no effect on boiling point
8 0
3 years ago
Ill give the brainliest answer to whoever helps me with this equation
vampirchik [111]

Answer: The percent yield for the NaBr is, 86.7 %

Explanation : Given,

Moles of FeBr_3 = 2.36 mol

Moles of NaBr = 6.14 mol

First we have to calculate the moles of NaBr

The balanced chemical equation is:

2FeBr_3+3Na_2S\rightarrow Fe_2S_3+6NaBr

From the reaction, we conclude that

As, 2 moles of FeBr_3 react to give 6 moles of NaBr

So, 2.36 moles of FeBr_3 react to give \frac{6}{2}\times 2.36=7.08 mole of NaBr

Now we have to calculate the percent yield for the NaBr.

\text{Percent yield}=\frac{\text{Experimental yield}}{\text{Theoretical yield}}\times 100

Experimental yield = 6.14 moles

Theoretical yield = 7.08 moles

Now put all the given values in this formula, we get:

\text{Percent yield}=\frac{6.14mol}{7.08mol}\times 100=86.7\%

Therefore, the percent yield for the NaBr is, 86.7 %

6 0
3 years ago
Which is the correct orbital diagram for carbon?
Brrunno [24]

Answer:

its 2p

Explanation:

In a neutral carbon atom, the 1s sublevel has one orbital with two electrons with opposite spins, represented by the arrows pointing in opposite directions. The 2s sublevel also has one orbital with two electrons, also with opposite spins. The 2p sublevel has three orbitals.

(i don"t understand this i just looked it up ._.

4 0
3 years ago
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