Answer:
- Addition of NH₃(g)
- Removal of N₂(g)
- Increase of temperature
- Pressure decrease
Explanation:
According to Le Chatelier's principle, if we apply an stress to a reaction at equilibrium, the system will try to shift the equilibrium in order to decrease the stress. If we add reactants, the equilibrium will shift toward the formation of more products (to the consumption of reactants) and vice versa.
The stresses we can apply to this equilibrium are the following:
- Addition of NH₃(g) : it is a product, thus its addition will result in a shift toward reactants.
- Removal of N₂(g): it is a reactant, thus its removal from the reaction mixture will result in a shift toward reactants.
- Increase of temperature: the reaction is <u>exothermic</u>, so it releases energy. <u>Energy is a product</u>. If we add energy (increase the temperature), we are adding a product, so the equilibrium will shift toward the reactants.
- Pressure decrease: because both reactants and products are in the gas phase. A decrease in pressure shifts an equilibrium to the side of the reaction with greater number of moles of gas. In this case, the reactants side has greater number of moles of gas (1 mol + 3 moles= 4 moles) than the products side (2 moles). Thus, the equilibrum will shift toward reactants.
I think its A sorry if im wrong
Answer:
Which set of orbitals are degenerate?
Degenerate is used in quantum mechanics to mean 'of equal energy. ' It usually refers to electron energy levels or sublevels. For example, orbitals in the 2p sublevel are degenerate - in other words the 2px, 2py, and 2pz orbitals are equal in energy, as shown in the diagram.
Explanation:
The milk has a mass concentration of 17 g/l of fat.
Answer:
THE INITIAL VOLUME OF THE STOCK SOLUTION IS 0.0392 L OR 39.2 mL
Explanation:
To calculate the volume of a solution before dilution, we make use of the dilution formula;
C1 V1 = C2 V2
C1 = the concentration of the stock solution = 15 M
V 1 = the volume of stock solution = ?
C2 = concentartion of final solution = 2.35 M
V2 = volume of final solution = 250 mL = 250/ 1000 = 0.25 L
Rearranging the formula, we obtain;
V1 = C2V2 / C1
V 1 = 2.35 * 0.25 / 15
V1 = 0.5875 / 15
V1 = 0.0392 L
the initial volume of the stock solution is 0.0392 L or 39.2 mL