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Triss [41]
2 years ago
13

Find the location of the object at times 0,1,2,. 1,000. Save the x-coordinates of the object at each time in a 1 ×1001 row vecto

r named a11. Save t
Physics
1 answer:
xeze [42]2 years ago
6 0

The x-coordinates of the object at each time in a 1 ×1001 row vector named a11 using coordinate.

Coordinates are distances or angles, represented by numbers, that uniquely perceive factors on surfaces of dimensions (second) or in space of 3 dimensions.

Coordinates are hard and fast values that help to expose the exact position of a factor within the coordinated aircraft.  A coordinate aircraft is a 2nd plane that's shaped by the intersection of perpendicular traces known as the x-axis and y-axis.

clear all

close all

alpha=-0.003;

w=0.05;

A=[1-alpha,-w;w,1-alpha];

A_inv=inv(A);

x0=[1;-1];

ans1=[1];

ans2=[-1];

for i=1:1000

x0=A_inv*x0;

ans1(i+1)=x0(1);

ans2(i+1)=x0(2);

end

ans1

Learn more about coordinate here:-brainly.com/question/17206319

#SPJ4

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A metal rod with a length of 22.0cm lies in the xy-plane and makes an angle of 37.9 degrees with the positive x-axis and an angl
Shtirlitz [24]

Answer:

Induced emf in the rod is, \epsilon=0.08262\ V

Explanation:

Given that,

Length of the rod, L = 22 cm = 0.22 m

Angle with x axis is 37.9 degrees with the positive x-axis and an angle of 52.1 degrees with the positive y-axis.

L=0.22(cos37.9\ i)+0.22(sin37.9\ j)

L=(0.173\ i+0.135\ j)\ m

Velocity of the rod, v = 6.8i m/s

Magnetic field, B=0.170i-0.24j-0.09k

The formula for the emf induced in the rod is given by :

\epsilon=(v\times B){\cdot}L

\epsilon=(6.8i\times (0.170i-0.24j-0.09k)){\cdot} (0.173\ i+0.135\ j)      

\epsilon=(0.612j-1.632k){\cdot}(0.173i+0.135j)      

\epsilon=0.08262\ V

So, the magnitude of the emf induced in the rod is 0.08262 volts. Hence, this is the required solution.                                      

8 0
3 years ago
Where does digestion begin?
Dafna11 [192]

Answer:

Digestion begins in the mouth, when you chew.

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3 years ago
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Two parallel-plate capacitors have the same dimensions, but the space between the plates is filled with air in capacitor 1 and w
Aleks [24]

Explanation:

The capacitance in two parallel-plate capacitors is:

C=\frac{K\epsilon_oA}{d}

For air, we have K_1=1

For plastic, we have K_2=2.25

Hence:

C_1=\frac{K_1\epsilon_oA}{d_1}=\frac{\epsilon_oA}{d_1}\\C_2=\frac{K_2\epsilon_oA}{d_2}=2.25(\frac{\epsilon_oA}{d_2})

a) Recall that the potential difference between the plates is the same (V_1=V_2=V). The electric field is given by:

E_1=\frac{V_1}{d_1}=\frac{V}{d_1}\\E_2=\frac{V_2}{d_2}=\frac{V}{d_1}

The potential difference is defined as:

V_1=\frac{Q_1}{C_1}=V\\V_2=\frac{Q_2}{C_2}=V

Replacing:

E_1=\frac{Q_1}{C_1d_1}\\E_2=\frac{Q_1}{C_1d_2}\\\\E_1d_1=\frac{Q_1}{C_1}\\E_2d_2=\frac{Q_1}{C_1}\\E_1d_1=E_2d_2\\\frac{E_1}{E_2}=\frac{d_2}{d_1}

b) The energy is defined as:

U=\frac{1}{2}CV^2

So:

U_1=\frac{1}{2}C_1V_1^2=\frac{1}{2}C_1V^2\\U_2=\frac{1}{2}C_2V_2^2=\frac{1}{2}C_2V^2\\U_1=\frac{1}{2}\frac{\epsilon_oA}{d_1}V^2\\U_2=\frac{1}{2}\frac{2.25\epsilon_oA}{d_2}V^2\\\frac{0.88U_2d_2}{\epsilon_oA}=V^2\\\frac{2U_1d_1}{\epsilon_oA}=V^2\\\frac{0.88U_2d_2}{\epsilon_oA}=\frac{2U_1d_1}{\epsilon_oA}\\\frac{U_1}{U_2}=0.44\frac{d_2}{d_1}

5 0
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Answer:

states that the rate of diffusion of gases is inversely proportional to their square roots

5 0
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A metal rod has a length of 123. cm at 200°C. At what temperature will the length be 92.6 cm if the coefficient of linear expans
mestny [16]

Answer:

\theta_{2} = 15400^0 C

Explanation:

The formula for linear expansivity, \alpha = \frac{l_{2} - l_{1}  }{l_{1} ( \theta_{2}  - \theta_{1} )}

original length, l₁ = 123 cm = 1.23 m

final length, l₁ = 92.6 cm =0.926 m

original temperature, θ₁ = 200°C

Linear expansivity, α = 2 * 10⁻⁵ °C⁻¹

Putting these values into the formula:

2 * 10^{-5}  = \frac{1.23 - 0.926  }{l_{1} ( \theta_{2}  -200 )}\\ \theta_{2}  -200 = \frac{0.304}{2 * 10^{-5} } \\\theta_{2} = 15200 + 200\\\theta_{2} = 15400^0 C

7 0
3 years ago
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