There's no way to tell for sure which plant will grow faster, because
we don't know if a plant gets any benefit from red light.
But we do know for sure that it won't be the one we shine green light on.
We know that green light is no use to green plants at all ... that's why
when green light falls on them, they don't even bother absorbing it.
They just let it bounce off, and that's why they look green to us.
Answer:
Fa=774 N
Fb=346 N
Explanation:
We will solve this problem by equating forces on each axis.
- On x-axis let forces in positive x-direction be positive and forces in negative x-direction be negative
- On y-axis let forces in positive y-direction be positive and forces in negative y-direction be negative
While towing we know that car is mot moving in y-direction so net force in y-axis must be zero
⇒∑Fy=0
⇒![Fa*sin(50)-Fb*sin(20)=0](https://tex.z-dn.net/?f=Fa%2Asin%2850%29-Fb%2Asin%2820%29%3D0)
⇒![Fa*sin(50)=Fb*sin(20)](https://tex.z-dn.net/?f=Fa%2Asin%2850%29%3DFb%2Asin%2820%29)
⇒![Fa=2.24Fb](https://tex.z-dn.net/?f=Fa%3D2.24Fb)
Given that resultant force on car is 950N in positive x-direction
⇒∑Fx=950
⇒![Fa*cos(20)+Fb*cos(50)=950](https://tex.z-dn.net/?f=Fa%2Acos%2820%29%2BFb%2Acos%2850%29%3D950)
⇒![2.24*Fb*cos(20)+Fb(50)=950](https://tex.z-dn.net/?f=2.24%2AFb%2Acos%2820%29%2BFb%2850%29%3D950)
⇒![Fb*(2.24*cos(20)+cos(50))=950](https://tex.z-dn.net/?f=Fb%2A%282.24%2Acos%2820%29%2Bcos%2850%29%29%3D950)
⇒![Fb=\frac{950}{2.24*cos(20)+cos(50)}](https://tex.z-dn.net/?f=Fb%3D%5Cfrac%7B950%7D%7B2.24%2Acos%2820%29%2Bcos%2850%29%7D)
⇒![Fb=\frac{950}{2.24*0.94+0.64}](https://tex.z-dn.net/?f=Fb%3D%5Cfrac%7B950%7D%7B2.24%2A0.94%2B0.64%7D)
⇒ ![Fb=\frac{950}{2.75}=345.5](https://tex.z-dn.net/?f=Fb%3D%5Cfrac%7B950%7D%7B2.75%7D%3D345.5)
⇒![Fa=2.24*Fb](https://tex.z-dn.net/?f=Fa%3D2.24%2AFb)
![=2.24*345.5](https://tex.z-dn.net/?f=%3D2.24%2A345.5)
![=773.93](https://tex.z-dn.net/?f=%3D773.93)
Therefore approximately, Fa=774 N and Fb=346 N
Answer:
force on electron will be equal to ![9.6\times 10^{-17}N](https://tex.z-dn.net/?f=9.6%5Ctimes%2010%5E%7B-17%7DN)
Explanation:
We have given magnitude of electric field E = 600 N/C
Charge on electron ![e=1.6\times 10^{-19}C](https://tex.z-dn.net/?f=e%3D1.6%5Ctimes%2010%5E%7B-19%7DC)
We have to find the electric force on the electron
Force in electric field is equal to
, here q is charge and E is electric field
So force will be equal to ![F=1.6\times 10^{-19}\times 600=960\times 10^{-19}=9.6\times 10^{-17}N](https://tex.z-dn.net/?f=F%3D1.6%5Ctimes%2010%5E%7B-19%7D%5Ctimes%20600%3D960%5Ctimes%2010%5E%7B-19%7D%3D9.6%5Ctimes%2010%5E%7B-17%7DN)
So force on electron will be equal to ![9.6\times 10^{-17}N](https://tex.z-dn.net/?f=9.6%5Ctimes%2010%5E%7B-17%7DN)
as long as the object is accelerating, all you have to do is to multiply the average velocity by 2 to get<span> the velocity.
To </span>find<span> the </span>acceleration<span>, you take velocity and divide it by the </span>time<span>. if it is traveling uniformly</span>