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3 years ago

How might deforestation lead to desertification

Physics

1 answer:

qwelly [4]3 years ago

6 0

If we keep cutting down tree's and if there are enough forest fires then it will turn into a desert....Hope it helps!

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Near to the point where I am standing on the surface of Planet X, the gravitational force on a mass m is vertically down but has

Gelneren [198K]

Answer: V = sqrt(2¥h^3)/3

Explanation:

8 0

3 years ago

The deck of a bridge is suspended 235 feet above a river. If a pebble falls off the side of the bridge, the height, in feet, of

Aleks04 [339]

Answer:

(a) 1, average velocity = -65.6 m/s

2, average velocity = -64.8 m/s

3, average velocity = -64.16 m/s

(b) The instantaneous velocity is -96 m/s

Explanation:

(a)

Average velocity is given by;

$y(t_2,t_1) = \frac{y(t_2) - y(t_1)}{t_2-t_1}$

(1)

$y(2.1,2) = \frac{(235-16*2.1^2) - (235-16*2^2)}{2.1-2}\\\\ y(2.1,2) = -65.6 \ m/s$

(2)

$y(2.05,2) = \frac{(235-16*2.05^2) - (235-16*2^2)}{2.05-2}\\\\ y(2.05,2) = -64.8 \ m/s$

(3)

$y(2.01,2) = \frac{(235-16*2.01^2) - (235-16*2^2)}{2.01-2}\\\\ y(2.01,2) = -64.16 \ m/s$

b. y = 235 - 16t²

The instantaneous velocity is given by;

v = dy /dt

dy / dt = -32t

when t = 3 s

v = -32(3)

v = -96 m/s

5 0

3 years ago

A paper airplane is thrown to the north from the top of a cliff with a speed of 2 km/h. the paper airplane land 15 minutes (0.25

lawyer [7]

B. 0.5 km to the North. if its going 2 km/h, just take the time (.25 hours) and divide it by the speed, and you've got distance.

3 0

3 years ago

Rearrange the equation current = voltage/resistance to express resistance in terms of current and voltage. Then solve the follow

MissTica

Answer:

Resistance, R = 13 ohms

Explanation:

The Ohm's law gives the direct relationship between the voltage, current and the resistance of the device. The relation is as follows :

$V=IR$

Where

I is the current

r is the resistance

The value of resistance is given by :

$R=\dfrac{V}{I}$

According to given data,

Voltage of the circuit, V = 130 V

Current rating of the circuit, I = 10 A

Resistance of the device,

$R=\dfrac{130\ V}{10\ A}$

R = 13 ohms

So, the resistance of the device is 13 ohms. Hence, this is the required solution.

3 0

3 years ago

Find the magnitude of u × v and the unit vector parrallel to u × v in the direction of u × v. u = 2i + 2j - k, v = -i + k

IrinaVladis [17]

Answer:

magnitude = 3

unit vector = $\frac{2i}{3} - \frac{j}{3} - \frac{2k}{3}$

Explanation:

Given vectors:

u = 2i + 2j - k

v = -i + k = -i + 0j + k

(a) u x v is the cross product of u and v, and is given by;

$u X v = \left[\begin{array}{ccc}i&j&k\\2&2&-1\\-1&0&1\end{array}\right]$

u x v = i(2+0) - j(2 - 1) + k(0 - 2)

u x v = 2i - j - 2k

Now the magnitude of u x v is calculated as follows:

| u x v | = $\sqrt{2^2 + (-1)^2 + (-2)^2}$

| u x v | = $\sqrt{4 + 1 + 4}$

| u x v | = $\sqrt{9}$

| u x v | = 3

Therefore, the magnitude of u x v is 3

(b) The unit vector û parallel to u x v in the direction of u x v is given by the ratio of u x v and the magnitude of u x v. i.e

û = $\frac{u X v}{|u X v|}$

u x v = 2i - j - 2k [<em>calculated in (a) above</em>]

|u x v| = 3 [<em>calculated in (a) above</em>]

∴ û = $\frac{2i - j - 2k}{3}$

∴ û = $\frac{2i}{3} - \frac{j}{3} - \frac{2k}{3}$

4 0

3 years ago