The same braking force does work on these objects to slow them down. The work done is equal to their change in kinetic energy:
FΔx = 0.5mv²
F = force, Δx = distance traveled, m = mass, v = speed
Isolate Δx:
Δx = 0.5mv²/F
Calculate Δx for each object.
Object 1: m = 4.0kg, v = 2.0m/s
Δx = 0.5(4.0)(2.0)²/F = 8/F
Object 2: m = 1.0kg, v = 4.0m/s
Δx = 0.5(1.0)(4.0)²/F = 8/F
The two objects travel the same distance before stopping.
<span>Given temperature ϑ = 56°C. Formula: speed of sound c = 331.3 + 0.606 × ϑ.Atϑ = 56°C the speed of sound c = 331.3 + 0.606 × 56 = 365.2 m/s.</span>
Answer: C. (Force = 2, time = 4.5)
Explanation:
J = FΔt
A. J = 5*2
A. J = 10
B. J = 1*8.5
B. J = 8.5
C. J = 2*4.5
C. J = 9
D. J = 3*2
D. J = 6
Sound waves travel through the air to your eardrum
She performed a lot of work