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Galina-37 [17]
2 years ago
9

State Graham's law and state in which sector it falls​

Physics
2 answers:
boyakko [2]2 years ago
5 0

Answer:

states that the rate of diffusion of gases is inversely proportional to their square roots

solmaris [256]2 years ago
4 0

Graham's law states that the rate of diffusion or effusion of two gases is inversely proportional to the square root of their molar masses

  • If two gases be x and y

For diffusion:-

\\ \sf\longmapsto \dfrac{V_x}{V_y}=\sqrt{\dfrac{m_y}{m(x}}

  • m means molar mass

For effusion

\\ \sf\longmapsto \dfrac{R_x}{R_y}=\sqrt{\dfrac{m_y}{m_x}}

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A force platform is a tool used to analyze the performance of athletes measuring the vertical force that the athlete exerts on t
Phoenix [80]

Answer:

a.I=981.34 N*s

b.v_f=3.96 m/s

c.v_{f1}=3.63m/s

d.y_f=0.673m

Explanation:

Given: m=67kg, h=0.720m, 0

a.

I=\int\limits^{t_1}_{t_2} {F(t)} \, dt

F(t)=9200*t-11500t^2

I=\int\limits^{0.8s}_{0s}{9200*t-11500*t^2} \, dt

I=4600*t^2-3833.3*t^3|(0.80,0)

I=2944-1962.66=981.35

I=981.34 N*s

b.

v_f^2=v_i^2+a*y'

Starting from the rest

v_f^2=0+2*9.8m/s^2*0.80s

v_f^2=15.68

v_f=\sqrt{15.68m^2/s^2}=3.96 m/s

c.

I_{total}=p_f

I_1-m*g*d=m*v_{f1}-m*v_f

981.34-67kg*9.8m/s^2*0.720=67.0kg*v_{f1}-67.0kg*(-3.96m/s)

Solve to vf

v_{f1}=3.63m/s

d.

v_f^2=v_i^2+2*a*y_f'

y_f'=v_i/2*a =(3.63m/s)^2/2*9.8m/s^2

y_f=0.673m

7 0
3 years ago
What are the condition required work to be done
Wewaii [24]

Answer:

The first is that the object moves

7 0
3 years ago
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What is the value of g on the surface of saturn? assume msaturn = 5.68×1026 kg and rsaturn = 5.82×107 m?
yKpoI14uk [10]
<span>F = GMm/r^2 but we don't want force we want acceleration. F = ma combining the two ma = GMm/r^2 cancelling m from both sides a = GM/r^2 where G is the universal gravitational constant M is the mass of Saturn and r is the radius of Saturn. g(Saturn) = a = (6.67x10^-11m^3kg^-1s^-2)(5.68x10^26 kg)/(5.82x10^7m)^2 g = 11.18 m/s^2 round to 11.2 m/s^2</span>
7 0
3 years ago
A parallel-plate capacitor is made from two aluminum-foil sheets, each 3.0 cm wide and 5.00 m long. Between the sheets is a mica
Evgen [1.6K]

This question is incomplete, the complete question is;

A parallel-plate capacitor is made from two aluminum-foil sheets, each 3.0 cm wide and 5.00 m long. Between the sheets is a mica strip of the same width and length that is 0.0225 mm thick. What is the maximum charge?

(The dielectric constant of mica is 5.4, and its dielectric strength is 1.00×10⁸ V/m)

Answer: the maximum charge q is 716.85 μF

Explanation:

Given data;

with = 3.0 cm = 0.03

breathe = 5.0 m

Area = 0.03 × 5 = 0.15 m²

dielectric strength E = 1.00 × 10⁸

∈₀ = 8.85 × 10⁻¹²

constant K = 5.4

maximum charge = ?

the capacitor C = KA∈₀ / d

q = cv so c = q/v

now

q/v = KA∈₀ / d

q =  vKA∈₀/d = EKA∈₀

we substitute

q = (1.00 × 10⁸) × 5.4 × 0.15 ×  8.85 × 10⁻¹²    

q = 716.85 × 10⁻⁶ F

q = 716.85 μF

the maximum charge q is 716.85 μF

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3 years ago
When an alarm clock rings, how will nearby air particles move in relation to the direction of the sound waves? A) Perpendicular
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Parallel to the direction of the waves
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3 years ago
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