Question

A fidget spinner experiences a constant torque of 1.4 N.m. If the spinner is initially at rest, what is its angular momentum 2.0 s later?

Answer 1

Answer:

$2.8N-msec$

Explanation:

We have given torque $\tau =1.4N-m$

Initial time $t_1=0\ sec$

Final time $t_2=2\ sec$

There is relation between angular momentum and torque

that is $\frac{dL}{dt}=\tau$

$dL=\tau dt$

$\int dL=\tau \oint_{t_1}^{t_2}dt$

$L=\tau (t_1-t_2)=1.4\times (2-0)=2.8N-msec$