The answer pleaseeeeeee

The longest pipe on a certain organ is 5.34 m. (a) what is the frequency f3 (at 0.00°c) if the pipe is closed at one end?

-Dominant- [34]

For a pipe open at both ends, fund frequency (Fo) given byFo = v /2L

v = velocity of sound = 340 m/s (at about 20ºC)

Fo = 340/2*5.34 = 31.8 Hz

While for the one closed at one end and open at the other end...

For a pipe open at one end, fund frequency (Fo) given byFo = v/4L

Fo = 340/4*5.34= 15.9 Hz

7 0

3 years ago

A pitot tube indicates a pressure of 155 kPa when placed in an air stream in which the temperature is 15°C and the Mach number i

mel-nik [20]

To solve this problem we will start by defining the relationship of the pitot tube and the value indicated in the pressure. We will take advantage of this relationship to obtain a ratio between the defined pressures and proceed to calculate the total and static pressure of the system through the correlation of pressure in isotropic systems. Finally we will perform this same procedure for pressure. Pitot tube measure the total pressure minus static pressure, then

$p_0 - p = 155kPa$

$\frac{p_0}{p} -1 = \frac{155}{p}$

$\frac{p_0}{p} = \frac{155}{p} +1$

Express the total pressure and static pressure ratio

$\frac{p_0}{p} = [1+\frac{\gamma-1}{2}M^2]^{\frac{\gamma}{\gamma-1}}$

$\frac{155}{p} +1 = [1+\frac{1.4-1}{2}(0.7)^2]^{\frac{1.4}{1.4-1}}$

$\frac{155}{p} +1=1.3871$

$p = 400.4kPa$

Hence the static pressure is 400.4kPa

Express stagnation to static temperature ratio,

$\frac{T_0}{T} = 1+\frac{\gamma-1}{2}M^2$

$\frac{T_0}{(15+273)K} = 1+\frac{1.4-1}{2}(0.7)^2$

$T_0 = 316.224K$

Therefore the stagnation temperature is 316.224K

5 0

3 years ago

elastic collision is a collision in which there is absolutely no loss of kinetic energy true or false

MrRa [10]

True because my physics notes say so

8 0

3 years ago

A bicyclist starting from rest applies a force of F 195 N to ride his bicycle across flat ground for a distance of d- 290 m befo

laila [671]

Answer: a) 56,550 J b) 30.1 m/s c) 321 m

Explanation:

a) By definition, work, is the process that does an applied force, in order to produce a displacement in the same direction than the applied force, and can be written as follows;

W = F. d. (scalar product of two vectors)

In this case, as the force is parallel to the displacement, work is directly equal to the product of the applied force times the displacement (in magnitude), so we can write the following:

W = F. D = 195 N. 290 m = 56,550 J

b) In absence of friction, the work done by the force is equal to the change in the kinetic energy, as it can be showed using the work-energy theorem.

So, in this case, we can put the following:

W = ΔK ⇒F. D = 1/2 mv²

Solving for v, we get:

v=√2.F.D/m = 30.1 m/s

c) Now, if we assume that there is no friction between the bike and the ground, all the kinetic energy must become gravitational potential energy, at some height h.

We can write the following equation

m.g. h = 1/2 mv²

Simplifying, and taking g = 9.8 m/s², we can find h:

h= 46.2 m

Now, we need to know the distance travelled up the incline, which is related with the height h, by the angle that the incline does with the horizontal, as follows:

sin 8.29° = h /d ⇒ d= h / sin 8.29° = 46.2 m / sin 8.29° = 321 m

6 0

3 years ago

When a bag of apples and a single apple are dropped at the same time from the same height, why do they both hit the ground at th

Yuliya22 [10]

The bigger Mass takes more Force to accelerate to the ground. The smaller Mass takes less Force to accelerate toward the ground. Coincidentally gravity exerts more force on the bigger mass and less force on the smaller Mass. The result is that all objects fall with the same acceleration. All objects reach the same speed after the same falling time. And all dropped objects hit the ground at the same time. We've known this for about 300 years.

7 0

3 years ago