All categories

3 years ago

Metals in group 1 on the periodic table most commonly form which type of ion

Physics

1 answer:

givi [52]3 years ago

7 0

Answer:

Group 1 - the alkali metals. The Group 1 elements in the periodic table are known as the alkali metals.

Explanation:

You might be interested in

What equation gives the position at a specific time for an object with constant acceleration?

malfutka [58]

Given constant acceleration, we can get the final position of an object in terms of both its initial velocity and its acceleration using one of the equations of motion.

The equation that we will use is:
Xf = Xi + Vi*t + (1/2)*a*t^2
where:
Xf is the final position of the object
Xi is the initial position of the object
Vi is the initial velocity of the object
t is the time
a is the constant given acceleration

4 0

3 years ago

How does a mathematical model help you understand the science concepts? Give an example.

sveta [45]

Usually describes a system by a set of variables in a set of equations established relationships between the variables and variables maybe of many types real or integer numbers Boolean values of strings for example

4 0

3 years ago

A proton is moving in a circular orbit of radius 20 cm under a uniform magnetic field 0.3 t perpendicular to the velocity of the

Vladimir [108]

Answer:

v = 5.75 x 10⁶ m/s

Explanation:

The radius (r) of the circular orbit taken by a charged particle is related to its speed perpendicular to a magnetic field of strength B, and is given by

r = $\frac{mv}{qB}$ --------------(i)

Where,

q = charge of the particle

m = mass of the particle

Making v subject of the formula in equation (i) above gives

v = $\frac{qBr}{m}$ -------------------(ii)

Given;

r = 20cm = 0.2m

B = 0.3T

v = unknown

q = charge of proton = 1.6 x 10⁻¹⁹ C

m = mass of the proton = 1.67 x 10⁻²⁷kg

Substitute the values of m, q, B and r into equation (ii) above to get;

v = $\frac{1.6 * 10^{-19} * 0.3 * 0.2} {1.67*10^{-27} }$

Solving for v gives:

v = 5.75 x 10⁶ m/s

Therefore, the velocity of the proton is 5.75 x 10⁶ m/s

4 0

3 years ago

The momentum of an object is determined to be 7.2 X 10-3 kg m/s. Express this quantity as provider or use any equivalent unit.

olasank [31]

There could be more than just one answer, since kilograms can be converted to grams, to miligrams, etc.

$7.2\frac{g.m}{s}$

$7200\frac{mg.m}{s}$

Why?

Let's remember some conversion factors to work with kilograms (kg)

$1kg=1000g=1x10^{3}g \\1kg=1,000,000mg=1x10^{6}mg \\1g=1000mg=1x10^{3}mg$

So, we are given the momentum:

$momentum=7.2x10^{-3} \frac{kg.m}{s}$

We can rewrite the units of the momentum (equivalent) as follow:

$momentum=7.2x10^{-3}kg \frac{m}{s}=7.2x10^{3} x10^{-3}g\frac{m}{s}=7.2\frac{g.m}{s}$

and

$momentum=7.2x10^{-3}kg \frac{m}{s}=7.2x10^{3} x10^{6}mg\frac{m}{s}=7.2x10^{3}\frac{mg.m}{s}$

Note: There could be more equivalent units for the momentum, in example, we could work with equivalent units for meters (distance) and seconds (time).

Have a nice day!

8 0

3 years ago

Read 2 more answers

A block of mass 0.254 kg is placed on top of a light, vertical spring of force constant 5 100 N/m and pushed downward so that th

ryzh [129]

Answer:

8.86 m

Explanation:

According to the law of conservation of energy, the elastic potential energy initially stored in the spring will be converted into gravitational potential energy of the block when it is at its maximum height:

$\frac{1}{2}kx^2 = mgh$

where

k = 5100 N/m is the spring constant

x = 0.093 m is the spring compression

m = 0.254 kg is the mass of the block

g = 9.8 m/s^2 is the acceleration due to gravity

h is the maximum height of the block

Solving the equation for h, we find

$h=\frac{kx^2}{2mg}=\frac{(5100 N/m)(0.093 m)^2}{2(0.254 kg)(9.8 m/s^2)}=8.86 m$

3 0

3 years ago