Metals in group 1 on the periodic table most commonly form which type of ion
1 answer:
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<h2>Answer: the falling time</h2>
Explanation:
When a body or object falls, basically two forces act on it:
1. The force of air friction, also called<em> </em><u><em>"drag force"</em></u> :
(1)
Where:
is the drag coefficient
is the density of the fluid (air for example)
is the velocity
is the transversal area of the object
So, this force is proportional to the transversal area of the falling element and to the square of the velocity.
2. Its <u>weight </u>due to the gravity force :
(2)
Where:
is the mass of the object
is the acceleration due gravity
So, at the moment <u>when the drag force equals the gravity force, the object will have its terminal velocity:</u>
(3)
(4)
(5) This is the terminal velocity
As we can see, there is no "falling time" in this equation.
Therefore, the terminal velocity is not dependent on the falling time.
1) In a circular motion, the angular displacement 
is given by
where S is the arc length and r is the radius. The problem says that the truck drove for 2600 m, so this corresponds to the total arc length covered by the tire:
. Using the information about the radius, 
, we find the total angular displacement:
2) If we put larger tires, with radius
, the angular displacement will be smaller. We can see this by using the same formula. In fact, this time we have:
where S is the arc length and r is the radius. The problem says that the truck drove for 2600 m, so this corresponds to the total arc length covered by the tire:
2) If we put larger tires, with radius