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3 years ago

What is the acceleration of a car that goes from 0m/s to 60m/s in 5 seconds?

Physics

2 answers:

UkoKoshka [18]3 years ago

6 0

The answer would be D

vlada-n [284]3 years ago

3 0

There is no acceleration

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A heavy flywheel rotating on its central axis is slowing down because of friction in its bearings. At the end of the first minut

Soloha48 [4]

Answer:

ω₂ = 93.6 rev / min

Explanation:

ω₀ = 260 rev / min

ω₁ = 0.68*ω₀ = 0.68*(260 rev / min) = 176.8 rev / min

ω₂ = ?

t₁ = 1 min

t₂ = 2 min

We can apply the equation:

ω₁ = ω₀ + α*t₁ ⇒ α = (ω₁ - ω₀) / t₁

⇒ α = (176.8 rev / min - 260 rev / min) / 1 min = - 83.2 rev / min²

then we can use the same formula, knowing the angular acceleration:

ω₂ = ω₀ + α*t₂ ⇒ ω₂ = (260 rev / min) + (- 83.2 rev / min²)*(2 min)

⇒ ω₂ = 93.6 rev / min

6 0

4 years ago

Citez un exemple de réaction endothermiques

Fiesta28 [93]

Réponse/explication:

La réaction qui produit de l'hydrogène et de l'oxygène à partir d'eau est endothermique. Certains changements de phase comme la vaporisation, la fusion ou la sublimation et la plupart des réactions de décomposition chimique sont endothermiques.

4 0

3 years ago

In a maneuver, the jet comes in for a landing on solid ground with a speed of 115 m/s, and its acceleration can have a maximum m

V125BC [204]

Answer:

17.1130952381 s

Explanation:

t = Time taken

u = Initial velocity = 115 m/s

v = Final velocity = 0

s = Displacement

a = Acceleration = -6.72 m/s² (negative as it is decelerating)

From the equations of motion

$v=u+at\\\Rightarrow t=\dfrac{v-u}{a}\\\Rightarrow t=\dfrac{0-115}{-6.72}\\\Rightarrow t=17.1130952381\ s$

The minimum time required to stop is 17.1130952381 s

$v^2-u^2=2as\\\Rightarrow s=\dfrac{v^2-u^2}{2a}\\\Rightarrow s=\dfrac{0^2-115^2}{2\times -6.72}\\\Rightarrow s=984.00297619\ m$

The distance that is required for the jet to stop is 0.98400297619 km which is greater than 0.8 km. So, the jet cannot land on a small tropical island airport.

4 0

3 years ago

In 1990, a pizza with a radius of 18.0 m was made in South Africa. Suppose you make an air-filled capacitor with parallel plates

Mazyrski [523]

Explanation:

We have,

Radius of pizza, r = 18 m

Potential difference, V = 575 V

Stored electrical potential energy, E = 3.31 J

The area if an air-filled capacitor with parallel plates is equal to that of the pizza. It means, $A=\pi r^2=\pi (18)^2=1017.87\ m^2$