All categories

2 years ago

Hi I don't know how to do this

Mathematics

1 answer:

Elena-2011 [213]2 years ago

5 0

Using a system of equations, the weight of 5 apples, 2 oranges are 4 bananas is given as follows:

B. 1147 gm.

<h3>What is a system of equations?</h3>

A system of equations is when two or more variables are related, and equations are built to find the values of each variable.

In this problem, the variables are:

Variable x: Weight of an apple.

Variable y: Weight of an orange.

Variable z: Weight of a banana.

Considering the data given, the equations are:

3x + 5y = 928.

4y + 6z = 1088.

5x + 3z = 799.

From the first equation:

3x = 928 - 5y.

x = 309.33 - 1.667y.

From the second equation:

6z = 1088 - 4y

z = 181.33 - 0.667y

Replacing in the third equation:

5x + 3z = 799

5(309.33 - 1.667y) + 3(181.33 - 0.667y) = 799

10.336y = 12961.64

y = 1291.64/10.336

y = 125 gm.

The other weights are:

x = 309.33 - 1.667y = 309.33 - 1.667 x 125 = 101 gm.

z = 181.33 - 0.667y = 181.33 - 0.667 x 125 = 98gm.

The weight of 5 apples, 2 oranges are 4 bananas is:

5x + 2y + 4z = 5 x 101 + 2 x 125 + 4 x 98 = 1147 gm, option B.

More can be learned about a system of equations at brainly.com/question/24342899

#SPJ1

You might be interested in

What is the difference x/x^2-16-3/x-4

kenny6666 [7]

General Idea:

When simplifying a rational expression, we need to do the below steps:

(i) Factor the Denominator of each fraction

(ii) Identify the Least Common Denominator (It is the product of prime factors involved with its highest exponent)

(iii) Identify and rewrite the equivalent fraction with the desired LCD.

(iv) Once the denominator are same, Combine the numerator.

Applying the concept:

What is the difference x/x^2-16-3/x-4

I assume that you mean to type the expression $\frac{x}{x^{2}-16} -\frac{3}{x-4}$

Step 1: Factoring $x^{2} -16$

$x^{2} -16=x^{2} -4^{2} =(x+4)(x-4)$

Step 2: Identifying the LCD, we get $(x+4)(x-4)$

Step 3: Rewriting the second fraction by multiplying x+4 on both top and bottom of second fraction so that we get the LCD.

$\frac{x}{x^2-16}-\frac{3}{x-4}=\frac{x}{(x+4)(x-4)} -\frac{3*(x+4)}{(x-4)*(x+4)} Step 4: Combine like terms since the denominators are same[tex] \frac{x-3(x+4)}{(x+4)(x-4)} =\frac{x-3x-12}{(x+4)(x-4)}=\frac{-2x-12}{(x+4)(x-4)} =\frac{-2(x+6)}{(x+4)(x-4)}$