Question

8. The pulley is assumed massless and frictionless and rotates freely about its axle. The blocks have masses m = 40 g and m₂ = 20 g, and block mi is pulled to the right by a horizontal force of magnitude F = 0.03 N. Find the magnitude of the acceleration of block m2 and the tension in the cord if the surface is frictionless. (2pt) m₂ a₂ T₂ T₂ T₁ m₁​

Answer 1

The magnitude of the acceleration of block m2  is 0.09 m/s² and the tension in the cord is 1.8 x 10⁻³ N.

Acceleration of the blocks

The acceleration of the blocks is calculated from the net force on the blocks.

∑F = ma

a = ∑F/m

a = (F) / (m₁ + m₂)

where;

• F is the horizontal force applied
• m₁ is mass of first block = 40 g = 0.04 kg
• m₂ is mass of the second block = 20 g = 0.02 kg

a = (0.03)/(0.04 + 0.02)

a = 0.09 m/s²

Tension due to block m₂

T = m₂a

T = (0.02 x 0.09) = 1.8 x 10⁻³ N

Thus, the magnitude of the acceleration of block m2  is 0.09 m/s² and the tension in the cord is 1.8 x 10⁻³ N.

Learn more about tension here: brainly.com/question/24994188

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