Friction, wind resistance, gravity, tension force
Answer:
Explanation:
When 2 gms of steam condenses to water at 100 degree latent heat of vaporization is releases which is calculated as follows
Heat released = mass x latent heat of vaporization
= 2 x 2260 = 4520 J
When 2 gms of water at 100 degree is cooled to ice water at zero degree heat is releases which is calculated as follows
Heat released = mass x specific heat x( 100-0)
= 2 x 4.2 x 100 = 840 J
When 2 gms of water at zero degree condenses to ice at zero degree latent heat of fusion is releases which is calculated as follows
Heat released = mass x latent heat of fusion
= 2 x 334 = 668 J
When 2 grams of steam at 100 degrees Celsius turns to ice at 0 degrees Celsius heat released will be sum of all the heat released as mentioned above ie
4520 + 840 +668 = 6028 J
Answer:
d = 98.67m
Explanation:
equation:
vf^2 = vi^2 + 2ad
(44m/s)^2 = (0m/s)^2 + 2(9.81m/s^2)(d)
1936m^2/s^2 = 19.62m/s^2(d)
divide both sides by 19.62m/s^2
d = 98.67m approximately
The answer is B. Have a good day! :)
C.) The rougher the surface of an object, the more friction it will produce.
think of sliding a rock on the street