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svet-max [94.6K]
4 years ago
12

The 0.18 kg block oscillates back and forth along a straight line on a frictionless horizontal surface. Its displacement from th

e origin is given by the following equation. x = (11 cm)cos[(15 rad/s)t + π/2 rad)] (a) What is the oscillation frequency? 2.39 Correct: Your answer is correct. Hz (b) What is the maximum speed acquired by the block? 165 Correct: Your answer is correct. cm/s At what value of x does this occur? cm (c) What is the maximum acceleration of the block? cm/s2 At what values of x does this occur? (positive then negative) cm and cm (d) What force, applied to the block, results in the given oscillation? ( N/m)x
Physics
1 answer:
AleksandrR [38]4 years ago
5 0

(a) f = 2.39 Hz

(b) Vmax = 165 cm/s

(c) amax = 24.75 m/s²

<u>Explanation:</u>

Given:

Mass, m = 0.18kg

displacement from the origin = ( 11 cm) cos [ ( 15 rad/s) t + (π / 2 rad)          -1

(a)

15 rad/s  will be the angular frequency, ω

So frequency is

f = ω / 2π

f = 15 / 2π

f = 2.39 Hz

(b)

we know,

Vmax = ω xmax

From equation 1, the value of xmax is 11cm

xmax = 0.11m

Vmax = 15 rad/s X 0.11m

Vmax = 1.65 m/s

Vmax = 165 cm/s

(c)

Maximum acceleration, amax = ω²xm

amax = (15)² X 0.11m

amax = 24.75 m/s²

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8 0
3 years ago
A physics major is cooking breakfast when he notices that the frictional force between the steel spatula and the Oiled Steel fry
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Answer:

N  = 6.67 N

Explanation:

The frictional or frictional force is a force that arises from the contact of two bodies and opposes movement.

The friction is due to imperfections and roughness, mainly microscopic, that exist on the surfaces of the bodies. Upon contact, these roughnesses engage with each other making movement difficult. To minimize the effect of friction, either the surfaces are polished or lubricated, since the oil fills the imperfections, preventing them from snagging.

As the frictional force depends on the materials and the force exerted on one another, its magnitude is obtained by the following expression:

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Data

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Read 2 more answers
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