Answer:
-a^2 + ab
Step-by-step explanation:
(a^2 - 2ab +b^2) + (2a^2 + 2ab + b2) = 3a^2 + 2b^2
(a^2 - b^2) + (a^2 + ab + 3b^2) = 2a^2 + 2b^2 + ab
subtract the first part from the second part:
(2a^2 + 2b^2 + ab) - (3a^2 + 2b^2) = -a^2 + ab
Answer:
A
Step-by-step explanation:
I did this one before and I still remember this problem
Draw a right triangle.


Arctangent (tan^-1) can be used to find theta.


Radius / diameter as a length cannot be negative, that's why '-16' is wrong.