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igomit [66]
2 years ago
10

Soru No 3

Engineering
1 answer:
Bumek [7]2 years ago
3 0
D) Never in a million years
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Estimate (a) the maximum, and (b) the minimum thermal conductivity values (in W/m-K) for a cermet that contains 85 vol% carbide
velikii [3]

Answer:

Explanation:

k_max = 26.9 w/mk

  k_min  =  22.33 w/mk

Explanation:

a) the maximum thermal conductivity is given as

K_MAX = k_m v_m + k_p v_p

where k_m is thermal conductvitiy of metal

k_p is thermal conductvitiy of carbide

v_m = proportion of metal in the cement = 0.15

v_p = proportion of carbide in the cement = 0.85

K_MAX = k_m v_m + k_p v_p

            = 66*0.15 + 20*0.85

           k_max = 26.9 w/mk

b) the minimum thermal conductivity is given as

k_min = \frac{ k_{carbide} *k_{metal}}{k_{metal} v_{carbide} +k_{carbide} v_{metal}}

          = \frac{20*66}{20*0.15 +66*0.85}

        k_min  = 22.33 w/mk

5 0
3 years ago
Please help i will give brainilest
Kay [80]

Answer:

I got u

Explanation:

this will help because using a electric object would be faster and more efficient than to use a manual thing

5 0
3 years ago
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You can divide a surface by drawing a line through it
SpyIntel [72]

Answer:

T

Explanation:

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Heat is applied to a rigid tank containing water initially at 200C, with a quality of 0.25, until the pressure reaches 8 MPa. De
creativ13 [48]

Answer:1747.53KJ/kg

Explanation:

Given data

Initial Temprature\left ( T_i\right )=200^{\circ}

Quality\left ( \chi\right )=0.25

Final pressure\left ( P_2\right )=8MPa

Given tank is rigid therefore specific Volume remains same

now calculating properties at 200^{\circ}

\nu _f=0.001156m^3/kg

\nu {fg}=0.126434m^3/kg

h_f=852.26KJ/kg

h_{fg}=1939.8KJ/kg

Now Specific volume of steam at 200^{\circ}

\nu _1=\nu _f+\chi \times \nu {fg}

\nu _1=0.001156+0.25\times 0.126434

\nu _1=0.03276m^3/kg

h_1=h_f+\chi \times h_{fg}

h_1=852.26+0.25\times 1939.8

h_1=1337.21 KJ/kg

Now \nu_1=\nu_2

0.03276=\nu_2

At 8 MPa and \nu =0.03276m^3/kg

\nu _g=0.02356

Since \nu _2\ is\ greater\ than \nu _g

therefore final state of steam is superheated at T=381^{\circ}

at this state h_2=3084.74 KJ/kg(obtained from steam table)

Therefore heat added

Q=h_2-h_1=3084.74-1337.21=1747.53 KJ/kg

3 0
3 years ago
What is the most important task of a spark plug?
Andrews [41]

Answer:

to break the side window of a car

Explanation:

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