Answer:
23.06262m^3/s
Explanation:
The volume flow rate of the water is determined from the needed power output and the elevation difference:
Where, height (h) =221m, power(w)=50MW=50*10^6w
Density of water (ρ)=1000kg/m^3
Efficiency of turbine(η)=100%=1
V=W/ρηgh
=50*10^6m^3/(1)*(1000)*(9.81)*(221)s=23.06262m^3/s
Answer:
And replacing in the Carnot efficiency we got:
Explanation:
For this case we can use the fact that the maximum thermal efficiency for a heat engine between two temperatures are given by the Carnot efficiency:
We have on this case after convert the temperatures in kelvin this:
And replacing in the Carnot efficiency we got:
And the maximum power output on this case would be defined as:
Where 
represent the heat associated to the deposit with higher temperature.
Answer:
G = 0.424
Explanation:
Ds = ( 0.278tr * V ) + (0.278 * V²)/ ( 19.6* ( f ± G))
Where Ds = stopping sight distance = 415miles = 126.5m
G = absolute grade road
V = velocity of vehicle = 52miles/hr
f = friction = 0 because the road is wet
tr = standard perception / reaction time = 2.5s
So therefore:
Substituting to get G
We have
2479.4G = 705.6G + 751.72
1773.8G = 751.72
G = 751.72/1773.8
G = 0.424
Answer:
What is percentage modulation in AM?
The percent modulation is defined as the ratio of the actual frequency deviation produced by the modulating signal to the maximum allowable frequency deviation.
