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castortr0y [4]
3 years ago
9

Which of the following is a direct result of technological improvements in the music industry?

Engineering
2 answers:
kykrilka [37]3 years ago
7 0

Answer:

Actually, the answer is increased music distribution opportunities.

Explanation:

I took the stem test and got it right.

notka56 [123]3 years ago
6 0

Answer: increased need for music technology professionals

Explanations:

In every industry now, the role of technology cannot be underestimated and the music industry is not left out.

The direct result of technological improvements in the music industry is that there will be increased need for music technology professionals. This is because due technological advancement, more professionals in music would be needed who have the required knowledge and expertise to handle the technologies.

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Increasing rake angle will decrease the tendency for Built-Up-Edge to form. a) True b) False
anygoal [31]

Answer:

a)True

Explanation:

While machining of ductile material and high feed and low cutting speed welding action take place between tool material and chip material this welding action is called built up edge. Built up edge action takes place due to high temperature.

To decrease the built up edge action

1. Increase the rake angle.

2. Increase the cutting speed

3. Decrease the feed rate

4. Use cutting fluid

7 0
3 years ago
calculate the magnitude of the force acting on the pin at D. Pin C is fixed in DE and bears against the smooth slot in the trian
Olenka [21]

Answer:

hello your question lacks the required diagram attached below is the diagram

answer : 58.47 N

Explanation:

The magnitude of the force acting on the Pin D

Fd = \sqrt{Dx^2 + Dy^2}

    = \sqrt{16.80^2 + 56^2}

    = 58.465 N

Dx = 16.80 N

Dy = 56 N

hello attached below is the detailed solution

8 0
3 years ago
A soil has the following Green-Ampt parameters Effective porosity 0.400 Initial volumetric moisture content-15% Hydraulic Conduc
Rudik [331]

Answer:

The graphs are attached below

Explanation:

Ans) We know,

F(t) = K(t - to) + zΔ∅ ln[(1 + F(t)/zΔ∅]

where K = hydraulic conductivity =0.1 cm/hr

z = capillary suction =20cm

 Δ∅ = ∅ (1 - Se)

 ∅ = effective porosity , Se = initial moisture content

 Δ∅ = 0.40(1 - 0.15)

Δ∅ = 0.34

Now, F(t) = 0.1(t - to) + 20(0.34) ln[ 1 + F(t)/6.8]

F(t) = 0.1(t - to) + 6.8 ln [1+ 0.147 F(t)]

Also, infiltration rate (f),

f = K [(zΔ∅ + F)/F]

f = 0.40 [6.8 + F]/F

Condition of ponding,

Ponding time tp = K zΔ∅ i(i-k)

where, i = rainfall rate (1cm/hr)

tp = 0.40(6.8) / 0.60

tp= 4.53 hours

Now, cumulative infiltraton at ponding Fp = i tp

Fp = 1 x 4.53 or 4.53 cm

For infiltration at time less then ponding time , infiltration rate = rainfall rate

For t = 0.25 hr , f = 1cm/hr ; F = 0.25 x 1 = 0.25 cm

For t = 0.50 hr , f = 1cm/hr ; F = 0.50 cm

For t = 0.75 hr , f = 1cm/hr ; F = 0.75 cm

For t = 1 hr , f = 1cm/hr ; F = 1cm/hr

For t > tp ,

Equivalent time origin(to),

to = tp - 1/K [ Fp - z Δ∅ ln (1+ Fp/zΔ∅)

to = 4.53 - 1/0.40[ 4.53 - 6.8 ln(1 + 0.66)

to = 4.53 - 2.5 ( 4.53 - 3.44)

to = 1.82 hr

Hence,

F = 0.10( t - 1.82) + 6.8 ln[ 1+ 0.147F(t)]

Solving above equation for t by assuming F, and further solving equation for infiltration rate

Ans (a) Following is required curve :

O.S 1-5 2 time Chr)ホー Lt 2 time Chr)

Ans (c) Following is required table :

Ans (d) For time step t = 0.25 hrs

At t < tp ; i = f = 1 cm/hr

F = i x t

F = 1 x 0.25

F = 0.25 cm  

 

5 0
4 years ago
11. Technician A says that gasoline storage containers should be painted red. Technician B says that any metal container may be
QveST [7]

Explanation:

1. Both a and b only

2. A only

3. B only

4.Neither a or b

6 0
3 years ago
You don't have to notify employees that a lockout/tagout is about to begin?
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Answer:

When the imposter is sus : O

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