Answer:
of cream will remain in the container.
Step-by-step explanation:
Given:
Amount of cream in the container = 
Amount of cream used to make crème brûlée = 
We need to find the amount of cream remain in the container.
Solution:
Now we can say that;
the amount of cream remain in the container is equal to Amount of cream in the container minus Amount of cream used to make crème brûlée.
framing in equation form we get;
amount of cream remain in the container = 
Now we will make the denominator common using LCM we get;
amount of cream remain in the container = 
Now denominators are common so we will solve the numerators.
amount of cream remain in the container = 
Hence
of cream will remain in the container.
Answer:
719 km/hour
Step-by-step explanation:
To find the unit rate you have to divide
3595/5 = 719 km/hour
Answer:
Option (4)
Step-by-step explanation:
From the graph attached,
A dotted line passes through two points (3, 1) and (-3, -3)
Let the equation of the given line is,
y = mx + b
where 'm' = slope of the line
b = y-intercept
Slope of a line passing through
and
is,
m = 
For the given points,
m = 
m = 
y-intercept 'b' = -1
Therefore, equation of the given line will be,

Since graphed line is a dotted line so it's representing an inequality(having < or > sign)
And the shaded part is below the dotted line,
Inequality will be,
y < 
Therefore, Option (4) will be the answer.
Answer:
Ok
Step-by-step explanation:
Answer:
The area of the shaded portion of the figure is
Step-by-step explanation:
see the attached figure to better understand the problem
we know that
The shaded area is equal to the area of the square less the area not shaded.
There are 4 "not shaded" regions.
step 1
Find the area of square ABCD
The area of square is equal to

where
b is the length side of the square
we have

substitute

step 2
We can find the area of 2 "not shaded" regions by calculating the area of the square less two semi-circles (one circle):
The area of circle is equal to

The diameter of the circle is equal to the length side of the square
so
---> radius is half the diameter
substitute


Therefore, the area of 2 "not-shaded" regions is:

and the area of 4 "not-shaded" regions is:

step 3
Find the area of the shaded region
Remember that the area of the shaded region is the area of the square less 4 "not shaded" regions:
so
---> exact value
assume

substitute