Question

Please help. was due 2 days ago

Answer 1

Answer:

$x=-\frac{1}{2},\frac{5}{2}$

Step-by-step explanation:

1) Split the second term in $4{x}^{2}-8x-5$  into two terms.

1- Multiply the coefficient of the first term by the constant term.

$4\times -5=-20$ to -8 and multiply to -−20?

2 and −10

3 - Split -8x as the sum of 2x and -10x.

$4x^2+2x-10x-5$

2)  Factor out common terms in the first two terms, then in the last two terms.

$2x(2x+1)-5(2x+1)=0$

3) Factor out the common term $2x+1$.

$(2x+1)(2x-5)=0$

4) Solve for $x$.

1 - Ask: When will (2x+1)(2x-5) equal zero?

When 2x + 1 = 0 or 2x - 5 = 0

2 - Solve each of the 2 equations above.

$x=-\frac{1}{2},\frac{5}{2}$