Since these two have the same power and variable, you can just subtract right away. It’s going to be 7x^1/5
Answer:
Measure of angle 2 and angle 4 is 42°.
Step-by-step explanation:
From the figure attached,
m∠ABC = 42°
m(∠ABD) = 90°
m(∠ABD) = m(∠ABC) + m(∠DBC)
90° = 43° + m(∠DBC)
m(∠DBC) = 90 - 43 = 47°
Since ∠ABC ≅ ∠4 [Vertical angles]
m∠ABC = m∠4 = 42°
Since, m∠3 + m∠4 = 90° [Complimentary angles]
m∠3 + 42° = 90°
m∠3 = 90° - 42°
= 48°
Since, ∠5 ≅ ∠3 [Vertical angles]
m∠5 = m∠3 = 48°
m∠3 + m∠2 = 90° [given that m∠2 + m∠3 = 90°]
m∠2 + 48° = 90°
m∠2 = 90 - 48 = 42°
m∠3+ m∠4 = 90° [Since, ∠3 and ∠4 are the complimentary angles]
48° + m∠4 = 90°
m∠4 = 90 - 48 = 42°
Therefore, ∠2 and ∠4 measure 42°.
Point Form: (1,-5)
Equation Form: x-1,y=-5
Answer:
y = 9x/5 + 50
Step-by-step explanation:
We are represent the information as coordinate (x,y)
If the cost for an order of 100 kilograms of steel bars is $230, this is expressed as (100, 230)
Also if the cost for an order of 150 kilograms of steel bars is $320, this is expressed as;
(150, 320)
Find the equation of a line passing through the points. The standard form of the equation is expressed as y = mx+c
m is the slope
c is the intercept
Get the slope;
m = y2-y1/x2-x1
m = 320-230/150-100
m = 90/50
m = 9/5
Get the y-intercept by substituting m = 9/5 and any point say (100, 230) into the expression y = mx+c
230 = 9/5(100)+c
230 = 9(20)+c
230 = 180 + c
c = 230-180
c = 50
Get the required equation
y = mx+c
y = 9/5 x + 50
Hence an equation for the cost of an order of steel bars (y) in terms of the weight of steel bars ordered (x) is y = 9x/5 + 50
Answer: 
Step-by-step explanation:
There is a double root at x=5 and a single root at x=-2, so we know f(x) is of the form
for some constant a.
To find a, we can substitute the coordinates of the y-intercept, (0, -50).

So, 