Answer:
answer would be the new area wil be 1/2 of the old area
Step-by-step explanation:
I'm pretty sure it's right hope this helps
Answer: The given logical equivalence is proved below.
Step-by-step explanation: We are given to use truth tables to show the following logical equivalence :
P ⇔ Q ≡ (∼P ∨ Q)∧(∼Q ∨ P)
We know that
two compound propositions are said to be logically equivalent if they have same corresponding truth values in the truth table.
The truth table is as follows :
P Q ∼P ∼Q P⇔ Q ∼P ∨ Q ∼Q ∨ P (∼P ∨ Q)∧(∼Q ∨ P)
T T F F T T T T
T F F T F F T F
F T T F F T F F
F F T T T T T T
Since the corresponding truth vales for P ⇔ Q and (∼P ∨ Q)∧(∼Q ∨ P) are same, so the given propositions are logically equivalent.
Thus, P ⇔ Q ≡ (∼P ∨ Q)∧(∼Q ∨ P).
Supplementary angles sum up to 180°, suppose the supplement of 161° is x. Then
161+x=180
solving for x we subtract 161 from both sides
161-161+x=180-161
x=19
thus the supplement is 19°
Obviously this will be a negative number
-2 - 14 = 5x - 3x
-16 = 2x
x = %28-16%29%2F2
x = -8 is the number
:
:
Check solution in the original statement: x=-8
3(-8) - 2 = 5(-8) + 14
-24 - 2 = -40 + 14
-26 = -26
Answer:
the answer to the question is C
