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2 years ago

I need help to complete this question

Mathematics

1 answer:

Bezzdna [24]2 years ago

3 0

The complete fractional question given in the above picture is 55/3 = 1 + 52/3 = 2 + 49/3 = 5 + 40/3 = 8 + 31/3 = 10 + 25/3

<h3>Fraction</h3>

Let

Each empty box = x

55/3 = 1 + x/3

55/3 = (3+x) / 3

55/3 × 3 = 3 + x

55 = 3 + x

55 - 3 = x

52 = x

55/3 = 2 + x/3

55/3 =(6+x) / 3

55/3 × 3 = 6+x

55 = 6 + x

55 - 6 = x

49 = x

55/3 = x + 40/3

55/3 = (3x+40) / 3

55/3 × 3 = 3x + 40

55 = 3x + 40

55 - 40 = 3x

15 = 3x

x = 15/3

x = 5

55/3 = x + 31/3

55/3 = (3x+31) / 3

55/3 × 3 = 3x + 31

55 = 3x + 31

55 - 31 = 3x

24 = 3x

x = 24/3

x = 8

55/3 = 10 + x/3

55/3 = (30+x) / 3

55/3 × 3 = 30 + x

55 = 30 + x

55 - 30 = x

25 = x

Learn more about fraction:

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3 years ago

beginning at sea level a scuba diver dove 1 2/3 feet into the water , and then dove an additional 3 2/5 feet at what elevation i

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The given details are illustrations of addition and subtractions of fractions. The scuba driver is at an elevation of $-5\frac{1}{15}$ ft below the sea level.

Given that:

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$n_2 = 3\frac 25$ ---- the additional dive

From the question, we understand that the diver starts at the sea level.

This is represented with 0ft.

So, the diver's elevation (d) is calculated as follows:

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So, we have:

$d = 0 - 1\frac 23 - 3\frac 25$

$d = - 1\frac 23 - 3\frac 25$

Convert fractions

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Take LCM

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Reduce fraction

$d = -5\frac{1}{15}$

The above value means that the diver's elevation is at $-5\frac{1}{15}$ ft below the sea level.

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