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natta225 [31]
2 years ago
11

A 26 kg bin is stationary on the driveway. The coefficient of static friction is 0.25. You pull on the bin with a force of 52 N

[E] and your friend pulls with a force of 110 N [W]. Will the bin move? Explain your reasoning.​
Physics
1 answer:
konstantin123 [22]2 years ago
8 0

The bin will not move because the frictional force is greater than the net force acting on the bin.

<h3>What is the net force acting on the bin?</h3>

The net force acting on the bin is obtained by subtracting the force acting on the Easterly direction from that acting in the Westerly direction.

Net force = 110 N - 52 N

Net force = 58 N

The frictional force acting on the bin is determined as well using the given formula:

Frictional force = coefficient of static friction * normal reaction

Norma reaction = 26 * 9.81

Normal reaction = 255.06 N

coefficient of static friction = 0.25

Frictional force = 0.25 * 255.06

Frictional force = 63.8 N

Since the frictional force is greater than the net force acting on the bin, the bin will not move.

In conclusion, the frictional force is the force that opposes relative between two objects at their surface of contact.

Learn more about frictional force at: brainly.com/question/13680415

#SPJ1

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As a 5.0 x 102 N basketball player jumps from the floor up toward the basket, the magnitude of the force of her feet on the floo
s2008m [1.1K]
Here is your answer:

First find the notations:

5.0×10^2=500.
1.0×10^3=1,000

Then you multiply:

1,000×500=500,000

Your answer is...
=500,000 or 5.0×10^4
8 0
4 years ago
A doctor has a patient blow on one side of a U-shaped tube that is partially filled with water and has a ball floating on the ot
natali 33 [55]

The patient apply pressure to his side of the tube is 15 x 10⁴ N/m². The correct option is D.

<h3>What is pressure?</h3>

The pressure is the amount of force applied per unit area. It is represented as

Pressure p = Force/Area

Given is a doctor has a patient blow on one side of a U-shaped tube that is partially filled with water and has a ball floating on the other side. The ball rises with a force of 150 N. The cross section are of the tube is 0.001 m³

The pressure applied is

p = 150 /0.001

p = 15 x 10⁴ N/m²

Hence, the patient apply pressure to his side of the tube is 15 x 10⁴ N/m².

Learn more about pressure.

brainly.com/question/12971272

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6 0
2 years ago
a vertical solid steel post 29cm in diameter and 2.0m long is required to support a load of 8200kg, ignore the weight of the pos
erik [133]

Answer:

The stress is  \sigma  =  1.218*10^{6} \  N/m^2

Explanation:

From the question we are told that

   The diameter of the post is  d =  29 \ cm  =  0.29 \  m

   The length is L  =  2.0 \  m

    The weight of the loading mass

Generally  the  radius of the post is mathematically represented as

     r =  \frac{0.29}{2}

=>   r = 0.145 \  m

Generally the area of the post is  

       A =  \pi r^2

=>     A =  3.14 *  0.145 ^2

=>     A =  0.066 \ m^2

Generally the weight exerted by the load is mathematically represented as

        F =  m  *  g

=>      F =  8200  *  9.8

=>      F =  80360 \  N

Generally the stress is mathematically represented as

         \sigma  =  \frac{F}{A}

=>      \sigma  =  \frac{80360 }{0.066}

=>      \sigma  =  1.218*10^{6} \  N/m^2

7 0
3 years ago
In a football game, a receiver is standing still, having just caught a pass. Before he can move, a tackler, running at a velocit
Nataliya [291]

Answer:

A) mr = 100 kg

B) Fr = 210N

C) Ft = -199.5N

Explanation:

By conservation of the momentum:

mt*Vo = (mr + mt) * Vf  Solving for mr:

mr = mt*Vo / Vf - mt = 100 kg

The average force on the receiver:

mr *(Vf - 0) = Fr * Δt    Solving for Fr:

Fr = 210 N

The average force on the tackler:

mt * (Vf - Vo) = Ft * Δt    Solving for Ft:

Ft = -199.5 N

8 0
3 years ago
Does the resistance of an object depend on the path current takes through it? Consider, for example, a rectangular bar—is its re
SVETLANKA909090 [29]

Answer:

Explanation:

An object's resistance depends on its form and the substance it is made from.  The electrical resistance R of the cylinder, as you might expect, is directly proportional to its length L, similar to a pipe's resistance to fluid flow. The longer the cylinder, the more charges of collisions with its atoms can occur. The bigger the cylinder diameter, the more current it can carry.

8 0
4 years ago
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