Answer:
u = 7.74 m/s and t = 1.82 s
Explanation:
Given that,
Harold threw a baseball 3 meters.
Harold is 2 meters tall.
The vertical distance = 3m
The final velocity at the maximum height is 0.
Let u is the initial velocity of the baseball. Using the first equation of motion to find it as follows :
Here, a = -g
He has thrown it with the speed of 7.74 m/s
Let t is the time taken by the ball to fall on the ground.
Harold is 2 meters tall. Using second equation of motion to find it.
u = -7.74 (as downward direction is taken as positive)
Hence, this is the required solution.
Answer:
student 1 is right and student 2 is wrong
Explanation:
In the graph that the two students are observing is a graph of energy and frequency vs. wavelength, this graph is constructed using the relationship between a wave and its wavelength and frequency.
c = λ f
therefore for all waves we have the speed salami.
Therefore student 1 is right and student 2 is wrong
Answer:
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The acid becomes nutralised
Answer:
velocity of rocket at the time of impact is 48.28 m/s
Explanation:
given,
rise of the rocket = 78 m
Velocity acquires by the rocket = 40 m/s
final velocity = 0 m/s
v = u + gt
0 = 40 - 9.81 × t
t = 4.08 s
now, calculation of displacement
= 40.8 m
total height = 40.8 + 78 = 118.8 m
velocity =
v = 48.28 m/s
velocity of rocket at the time of impact is 48.28 m/s