Two energy resources that do not depend on the sun's energy
2 answers:
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Answer:
elastic partial width is 2.49 eV
Explanation:
given data
ER E = 250 eV
spin J = 0
cross-section magnitude σ = 1300 barns
peak P = 20ev
to find out
elastic partial width W
solution
we know here that
σ = λ²× W / ( E × π × P ) ...................1
put here all value
σ = (0.286)² × W × / ( 250 × π × 20 )
1300 × = (0.286)² × W ×
/ ( 250 × π × 20 )
solve it and we get W
W = 249.56 ×
so elastic partial width is 2.49 eV
Answer:
The acceleration of each mass is the same, and approximately equal to
Explanation:
Notice that the mass of the whole system is: 30 kg + 40 kg = 70 kg
If we use a net force of 100 N on the combined system, we can find the acceleration imparted to the masses via Newton's second law: