Answer:
The magnitude of the force of friction equals the magnitude of my push
Explanation:
Since the crate moves at a constant speed, there is no net acceleration and thus, my push is balanced by the frictional force on the crate. So, the magnitude of the force of friction equals the magnitude of my push.
Let F = push and f = frictional force and f' = net force
F - f = f' since the crate moves at constant speed, acceleration is zero and thus f' = ma = m (0) = 0
So, F - f = 0
Thus, F = f
So, the magnitude of the force of friction equals the magnitude of my push.
In a completely inelastic collision, the two objects stick together after the collision.
Answer:
None, both objects will hit ground at the same time.
Explanation:
- Assuming no air resistance present, and that both objects start from rest, we can apply the following kinematic equation for the vertical displacement:
- As the left side in (1) is the same for both objects, the right side will be the same also.
- Since g is constant close to the surface of the Earth, it's also the same for both objects.
- So, the time t must be the same for both objects also.
Given Information:
Radius = r₁ = 150 m
Radius = r₂ = 73 m
Maximum speed = v₁ = 28.0 m/s
Required Information:
Maximum speed = v₂ = ?
Answer:
Maximum speed v₂ = 19.53 m/s
Explanation:
The maximum acceleration of the truck is
a = v²₁/r₁
a = 28²/150
a = 5.226 m/s²
Now if we change the radius to r₂ = 73 m
Then the maximum speed of the truck is
v₂ = √a*r₂
v₂ = √5.226*73
v₂ = 19.53 m/s
So the speed of the truck is decreased when the radius of curve is decreased.
