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Oksi-84 [34.3K]
2 years ago
13

To date, which of these has been used largely in creating clones? Metabolic profiling RNA sequencing Protein mapping Recombinant

DNA technology
Biology
1 answer:
cluponka [151]2 years ago
8 0

RNA sequencing technology has been used largely in creating clones.

<h3 /><h3>What is RNA sequencing?</h3>

RNA sequencing (RNA-Seq) makes use of high-throughput sequencing techniques to shed light on a cell's transcriptome.

Numerous RNA biology topics, such as single-cell gene expression, translation (the translatome), and RNA structure, can be studied using RNA-seq techniques (the structurome). Exciting new uses, such as spatial transcriptomics, are being investigated (spatialomics).

<h3>The steps in a typical RNA-sequencing experiment are as follows:</h3>
  1. Design experiment: Plan the experiment.
  2. Preparation of RNA. Purify and isolate the input RNA.
  3. Library preparation. Create cDNA from the RNA and add sequencing adapters.
  4. Sequence. cDNAs should be sequenced using a platform.
  5. Analysis.

Learn more about RNA sequencing here:

brainly.com/question/26277580

#SPJ1

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Three ways to transfer heat are by?
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Which of the following a synapomorphy linking dinosaurs and birds?
Readme [11.4K]

Answer:

d. furcula

Explanation:

Furcula

Furcula is a synapomorphy linking dinosaurs and birds .

The furcula is the structure formed by midline fusion of clavicles and this very  element is unique in the theropods as well . And is the most crucial for understanding the link between birds and the theropods .

The first suggestion was by Huxley in 1868 , and in 1870 , the key component of the debate is the presence of Frucula .

6 0
3 years ago
Why is DNA important to society as a whole?
lianna [129]
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2 years ago
Read 2 more answers
A proton has a speed of 3.0 × 106 m/s in a direction perpendicular to a uniform magnetic field, and the proton moves in a circle
jeyben [28]

Answer:

The magnitude of the magnetic field is 0.156 T.

Explanation:

Given that,

Speed of a proton, v=3\times 10^6\ m/s

Radius of the circular path, r = 0.2 m

When the proton enters in the circular path, the centripetal force is balanced by the magnetic force such that :

\dfrac{mv^2}{r}=qvB\sin\theta

q is the charge on proton

Here, \theta=90^{\circ}

\dfrac{mv^2}{r}=qvB\\\\B=\dfrac{mv}{qr}\\\\B=\dfrac{1.67\times 10^{-27}\times 3\times 10^6}{1.6\times 10^{-19}\times 0.2}\\\\B=0.156\ T

So, the magnitude of the magnetic field is 0.156 T. Hence, this is the required solution.

3 0
3 years ago
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