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2 years ago

An object 10mm in height is located 20cm from a crown glass spherical surface whose power is +10.00DS. Locate the image

Physics

1 answer:

Tasya [4]2 years ago

7 0

The image is present at 20cm from the crown glass spherical surface.

To find the answer, we need to know about the lens formula.

<h3>What's the lens formula?</h3>

It's (1/V)-(1/U)= (1/f)
V= image distance from the lens, U= object distance, f= focal length of the lens

<h3>What's the image distance, if object is present at 20cm from crown glass of power 10DS?</h3>

Focal length (f)= 1/ power = 1/10 = 0.1 m
U= -20cm = -0.2m (-ve sign due to sign convection)
(1/V)-(-1/0.2)= (1/0.1)

=> (1/V)+5=10

=> 1/V= 5

=> V=0.2m = 20cm

Thus, we can conclude that the image is present at 20cm.

Learn more about the lens formula here:

brainly.com/question/2098689

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Explanation:

From the question we are told that

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$l_o =\frac{l}{\sqrt{ 1 - \frac{v^2}{c^2 } } }$

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Considering b

Applying above equation

$l =l_o \sqrt{1 - [\frac{v}{c } ]}$

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$l=145 * \sqrt{1 - \frac{v_s^2}{c^2 } }$

$l =145 * \sqrt{ 1 - \frac{2.9 *10^{8}}{3.0*10^{8}} }$

$l = 37.13 \ LY$

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