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Salsk061 [2.6K]
3 years ago
9

What is the answer to life?

Physics
2 answers:
ivolga24 [154]3 years ago
8 0
The answer to life is different for everyone. There are ways to help you find out your personal answer to life, but in the end it's only you who can answer that question. Maybe you find it in a religion, in your sweetheart and family, at work, in friends, in books, etc. For example me: The purpose to my life is to work hard now so I can provide a safe future for my future wife and children, raise them up as people of good, grow old with the love of my life, die, and wait for the Lord's Second Coming. But as I said the answer to your question depends on your goals for life.
taurus [48]3 years ago
6 0
The answer to life is how ever you make it...... you can do anything with life that you would like.................. But make your choices worth it......
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What's an example for investigate
ludmilkaskok [199]
Investigate means to search for something or look in to something
8 0
3 years ago
Read 2 more answers
1. A soccer player kicks a soccer ball towards the goal. If she kicks it with a velocity of 24 m/s at an angle of 31 degrees abo
ruslelena [56]

Answer:

<em>The ball will go as high as 8.46 m</em>

Explanation:

<u>Projectile Motion</u>

It's the type of motion that experiences an object launched at a certain height above the ground and moves along a curved path exclusively under the action of gravity.

Being vo the initial speed of the object, θ the initial launch angle, and g the acceleration of gravity, then the maximum height hm can be calculated as follows:

\displaystyle h_m=\frac{v_o^2\cdot \sin^2\theta}{2g}

The soccer ball is kicked at a speed of vo=24 m/s at an angle of θ=31°. Taking the value of g=9.8 m/s^2, then:

\displaystyle h_m=\frac{24^2\cdot \sin^2 31^\circ}{2\cdot 9.8}

\displaystyle h_m=\frac{576\cdot 0.2653}{19.6}

h_m=7.80~m

The ball will go as high as 8.46 m

4 0
3 years ago
If the ultimate shear strength of steel is taken to be 3.00 109 Pa, what force is required to punch through a steel plate 1.60 c
photoshop1234 [79]

Answer:

Explanation:

Given

Ultimate shear strength \tau =3\times 10^9\ Pa

thickness of steel Plate t=1.60\ cm

Cross-sectional A=1.20\times 10^2\ cm^2

suppose d is the diameter of cross-section

\frac{\pi }{4}d^2=1.20\times 10^2

d=12.359\ cm

Shear area of circular cross-section

A_s=\pi dt

A_s=\pi \times 12.359\times 1.6

A_s=62.13\ cm^2

Shear Force F_s=A_s\times \tau

F_s=62.13\times 10^2\times 3000

F_s=18.639\ MN  

6 0
3 years ago
Please answer this and I will make you the BRAINLIST!!!!!!!! ✨✨✨
sweet-ann [11.9K]

Answer:

it may be efficient at first but over time there will be a lot of wasted energy.

Explanation:

I'm pretty sure

4 0
3 years ago
A point charge that is exactly q =3 mu or micro CC is at the origin. In this problem, assume that the Coulomb constant k = 8.99
Simora [160]

Answer:

(a) V1 = 8990.00 V

V2 = 8960.13 V

Explanation:

Parameters given:

q =3 mC

k = 8.99 * 10⁹ Nm²/C²

x1 = 3 m

x2 = 3.01 m

Electric potential is given as:

V = kq/r

Where

k = Coulombs constant

q = charge

r = distance

Potential at x1 is:

V1 = (8.99 * 10⁹ * 0.000003)/(3)

V1 = 8990.00V

Potential at x2 is:

V2 = (8.99 * 10⁹ * 0.003)/(3.01)

V2 = 8960.13 V

7 0
3 years ago
Read 2 more answers
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