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Salsk061 [2.6K]
3 years ago
9

What is the answer to life?

Physics
2 answers:
ivolga24 [154]3 years ago
8 0
The answer to life is different for everyone. There are ways to help you find out your personal answer to life, but in the end it's only you who can answer that question. Maybe you find it in a religion, in your sweetheart and family, at work, in friends, in books, etc. For example me: The purpose to my life is to work hard now so I can provide a safe future for my future wife and children, raise them up as people of good, grow old with the love of my life, die, and wait for the Lord's Second Coming. But as I said the answer to your question depends on your goals for life.
taurus [48]3 years ago
6 0
The answer to life is how ever you make it...... you can do anything with life that you would like.................. But make your choices worth it......
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Answer:

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Explanation:

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Suppose astronomers discover a radio message from a civilization whose planet orbits a star 35 light-years away. Their message e
Grace [21]

Answer:

The duration  is  T  =72 \  years /tex]Explanation:From the question we are told that     The  distance is  [tex]D  =  35 \ light-years = 35 *  9.46 *10^{15} = 3.311 *10^{17} \  m

  Generally the time it would take for the message to get the the other civilization is mathematically represented as

         t =  \frac{D}{c}

Here c  is the speed of light with the value  c =  3.08 *10^{8} \  m/s

=>     t =  \frac{3.311 *10^{17} }{3.08 *10^{8}}

=>     t =  1.075 *10^9 \ s

converting to years

           t =  1.075 *10^9 *  3.17 *10^{-8}

              t =  1.075 *10^9 *  3.17 *10^{-8}

            t =  34 \ years

Now the total time taken is mathematically represented as

      T  =  2*  t  +  2 + 2

=>   T  =  2* 34  +  2 + 2

=>   [tex]T  =72 \  years /tex]

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3 years ago
A photographer in a helicopter ascending vertically at a constant rate of accidentally drops a camera out the window when the he
maksim [4K]

Answer:

The time it takes for the camera to reach the ground is 5 s.

Explanation:

To solve this problem, we will use the free fall cinematic equation.

Since the helicopter ascends with constant speed, the camera falls to the ground only by the effect of gravity on it.

The speed at which the helicopter ascends is not specified in the statement, but according to a similar problem, we will use 12.5 \frac{m}{s}.

First, we must calculate the time and the maximum height at which the camera arrives after leaving the helicopter.

To calculate the maximum height to which it arrives, we will use the formula of vertical shot (since the camera leaves the helicopter with a speed upwards of 12,5 \frac{m}{s}).

V_{f} ^{2}=V_{0} ^{2} - 2 * g * h

Where:

V_{f}: final speed at maximum height.

V_{0}: initial speed when it falls from the helicopter.

g: gravity taken at 9.8 \frac{m}{s^{2} }

h: height reached from 60 m when leaving the helicopter

as V_{f}=0

0=(12,5\frac{m}{s}) ^{2} - 2 * 9,8\frac{m}{s^{2} } * h

clear h:

h=(12,5 \frac{m}{s^{2} } )^{2} / (2 * 9,8 \frac{m}{s^{2} })

h=7,97 m

Then we must calculate the time it takes to reach its maximum height:

V_{f}=V_{0} - g * t

t: time it takes to arrive from the moment it leaves the helicopter at its maximum height.

as V_{f}=0

0=12.5 \frac{m}{s} - 9.8 \frac{m}{s^{2} } * t

clearing t

t=12.5 \frac{m}{s} / 9.8 \frac{m}{s^{2} }

t=1.27 s.

Now we can calculate the time it takes to fall from the maximum height of 67.97 m.

The equation we will use is Y=v_{0}*t+(\frac{g*t^{2} }{2} )

where:

t: time it takes for the camera to fall.

Y: height from where the camera falls concerning the ground.

v_{0}: initial speed of the camera at the time of starting the fall.

g: acceleration of gravity, estimated at 9.8 \frac{m}{s^{2} }

Step 1: As the helicopter ascends with constant speed, the initial speed of the camera at the moment of falling is 0.

v_{0}=0

So the first term of our equation is nullified.

Step 2: To calculate the time it takes to fall, we clear "t" of the equation:

Y=\frac{(g*t^{2})}{2}

Y*2=(g*t^{2})

\frac{Y*2}{g}=t^{2}

\sqrt{\frac{Y*2}{g} }=t

Step 3: I replace the values with the incognites and get "t".

t=\sqrt{\frac{67,97m*2}{9,8\frac{m}{s^{2} } } }

t=3,73 s

The total time it takes for the camera to fall from the moment it leaves the helicopter is the sum of the time it takes to reach the maximum point of height and the time it takes to fall to the ground from that height.

t= 1,27 s + 3,73 s = 5 s

Have a nice day!

3 0
3 years ago
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