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yanalaym [24]
3 years ago
13

A flat plate maintained at a temperature of 80°C experiences a flow of atmospheric air at 0°C. If the temperature gradient at th

e plate’s surface at a given downstream-stream location is 43°C/mm, what is the local heat transfer coefficient?
Physics
1 answer:
dimulka [17.4K]3 years ago
4 0

Answer:

h =12.9 w/m2 k

Explanation:

we know that thermal conductivity of air K at 0 degree celcius = 0.024 w/mk

T_S = 80 Degree celcius

temperature gradient = -43 degree C/mm = - 43*1000 / m\frac{dT}{dx} = - 43*1000 / m

by fourier law

Q = -k_{air} A * \frac{dT}{dx}

\frac{Q}{A} = -0.024 *1*(-43000)

q = 1032 watt/m2

we know that from newton's law

q = h (T_s - T_∞)

1032 = h*(80 - 0)

h =12.9 w/m2 k

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sergiy2304 [10]

Answer:

23.96 N

Explanation:

From the question given above, the following data were obtained:

Mass of Chihuahua (m) = 3.63 kg

Velocity (v) = 3.3m/s

Time (t) = 0.50 s

Force (F) =?

Next, we shall determine the acceleration of the Chihuahua. This can be obtained as follow:

Velocity (v) = 3.3m/s

Time (t) = 0.50 s

Acceleration (a) =?

a = v/t

a = 3.3/0.5

a = 6.6 m/s²

Thus, the acceleration of the Chihuahua is 6.6 m/s².

Finally, we shall determine the force need to stop the Chihuahua as shown below:

Mass of Chihuahua (m) = 3.63 kg

Acceleration (a) = 6.6 m/s².

Force (F) =?

F = ma

F = 3.63 × 6.6

F = 23.96 N

Therefore, a force of 23.96 N is needed to stop the Chihuahua.

8 0
2 years ago
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Based on the most widely accepted scientific explanation, elements began to form shortly after the big bang. Which of the follow
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** URGENT** The voltage across the primary winding is 350,000 V, and the voltage across the secondary winding is 17,500 V. If th
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As we know that in transformers we have

\frac{V_s}{V_p} = \frac{N_s}{N_p}

here we know that

V_s = 17,500 Volts

V_p = 350,000 Volts

N_s = 600 coils

now from above equation we will have

\frac{17500}{350000} = \frac{600}{N_p}

N_p = 600\times \frac{350000}{17500}

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6 0
3 years ago
Point charges of 21.0 μC and 47.0 μC are placed 0.500 m apart. (a) At what point (in m) along the line connecting them is the el
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Answer:

a) x = 0.200 m

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E = 3.84*10^{-4} N/C

6 0
3 years ago
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