Find two numbers with a sum of 20 and a difference of 14
Make two equations
X+Y=20
X-Y=14
Now add x since y cancels out and add 20+14 To end up with
2x=34
Now divide 2 both sides to get x alone
2x/2=34/2
X=17
Now substitute x answer to first equation and solve for y
17+y=20
Subtract 17 both sides
Y= 3
Your two numbers are
3 and 17
Answer:
(0, -8)
Step-by-step explanation:
The distance must be equal from C to A and points B to D.
All you have to do is put the walking amount in for w and basketball in for b. Do it for all of these, if it is less than 400 or greater than 600, it is not a solution.
(4 x 40) + (5 x 40) = 360 so reject because it is less than 400.
I'll let you do the rest.
Which problem? I will help you if you tell me what problem it is.
I get you can’t get this I’m in 8th grade it’s hard as infierno what grade are you in
