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3 years ago

Can someone please help me

Mathematics

1 answer:

devlian [24]3 years ago

7 0

I believe it's the same as adding 8+3, but you add the negative sign to your answer
so 8+3 = (-?)

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guapka [62]

Answer:

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Step-by-step explanation:

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3 years ago

3<3x+6<24<br><br>i keep getting 1 < x < 6<br>but the answer says -1 < x < 6

lara [203]

3 < 3x+6
-3<3x
-1<x

3x+6<24
3x<18
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-1<x<6 the book is right

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3 years ago

Lewis directs the school marching band. He uses scale drawings of the football field to design marching formations for the band.

Andrews [41]

Answer:

Assuming you have the lengths in inches.

Do this: (length in inches * 10) x (length in inches * 10)

Step-by-step explanation:

There's information missing from this question. "The football field is 100 yards long and yards wide", but to find out the area of a rectangle you just need to times the two numbers together.

I assume you have a picture with the lengths in inches on, if you can see how many inches are on the scale drawing, times the inches by 10 for the length in yards for each side. Then times the two lengths (in yards) together for the area.

5 0

3 years ago

Read 2 more answers

A rhombus has four 6-inch sides and two 120-degree angles. From one of the vertices of the obtuse angles, the two latitudes are

nikitadnepr [17]

Answer:

Area(A)=Area(C)= $9 in^{2}$

Area(B)= $13.2 in^{2}$

Step-by-step explanation:

We begin with finding the angles a and b that from the drawing attached you can see that a=b.

Now, the sum of the internal angles of a rhomboid is equal to 360 degrees, with that we have:

120+120+a+b=360

240+2a=360

2a=120

a=60=b

Next, in the image you can see that the lines coming from the angle at the top 120 degrees vertex, divide the opposite sides by half, thus making two triangles with one side of 6 in and another of 3 in.

We can say from the drawing as well:

Area(A)+Area(B)+Area(C)=Area(rhomboid)

But, we can also say that Area(A)=Area(C)

So, starting with Area(A)

Area(A)=Area(triangle)= $\frac{b*h}{2}$ = $\frac{6*3}{2}$ = $9 in^{2}$

We can then calculate the area B, a rhomboid, or better, take the Total area of the figure and subtract the area of the two triangles.

Area(B)=Area(rhomboid)-Area(A)-Area(C)

Area(rhomboid)=b*h where b=6in and h is the perpendicular distance from the base to the top.

$h=[tex]6*cos(30)=5.20in$ The 30 degrees come from: 120-30-60=30, since the latitudes split the 120 angle in two equal parts and one that is the half of the obtuse angle.

Area(rhomboid)=5.20*6= $31.2 in^{2}$

Area(B)=Area(rhomboid)-Area(A)-Area(C)= $31.2 in^{2}$ - $9 in^{2}$ - $9 in^{2}$ = $13.2 in^{2}$

3 0

3 years ago