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baherus [9]
1 year ago
12

(05.02 MC) Solve 2 log x = log 64. Ox= 1.8 Ox=8 Ox= 32 Ox = 128

Mathematics
1 answer:
RoseWind [281]1 year ago
3 0

Answer:

x = 8

Step-by-step explanation:

2logx=log64\\logx^2=log64

now that both sides has log, you can remove them and leave it as:

x^{2} =64\\

take the square root of both sides:

x = [8, -8]\\x = 8

logarithmic equations can't have negative solutions, plus -8 isn't an option

i hope this helped!

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Describe in words how you would solve the linear system y = 3x + 1 and y = - 2x + 3.
Sergio [31]
We are using substitution to solve this problem.

y=3x+1
y=-2x+3
Make these equal each other: 3x+1=-2x+3
Add 2x to both sides: 3x+2x+1=-2x+2x+3
= 5x+1=3
Subtract 1 from both sides; 5x+1-1=3-1
= 5x=2
Divide 5 from both sides: 5x/5=2/5
X= 2/5
Plug X into one of the equations: y=3(2/5) +1
y=11/5(2.2)

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What is the value of f(-6) when f(x) =x^2+8x+10?
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f=36-48+10

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8 0
3 years ago
What are the 2 most common exponents you will deal with when finding roots?
alex41 [277]

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4 0
3 years ago
Hi!
solniwko [45]

Answer:

y = 1x - 4

Step-by-step explanation:

You have to solve for the x intercept on the equation

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That is the x intercept for that equation.

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That is the x intercept for that equation.

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3 years ago
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