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baherus [9]
1 year ago
12

(05.02 MC) Solve 2 log x = log 64. Ox= 1.8 Ox=8 Ox= 32 Ox = 128

Mathematics
1 answer:
RoseWind [281]1 year ago
3 0

Answer:

x = 8

Step-by-step explanation:

2logx=log64\\logx^2=log64

now that both sides has log, you can remove them and leave it as:

x^{2} =64\\

take the square root of both sides:

x = [8, -8]\\x = 8

logarithmic equations can't have negative solutions, plus -8 isn't an option

i hope this helped!

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Answer:

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14 miles im not sure

Step-by-step explanation:

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3 years ago
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Calculate the radicand of f(x)=x^2+20x+97 and state what it tells you about the roots of the function. Then solve the function u
Furkat [3]

Answer: The roots are x=-10 +- root 3.

Step-by-step explanation:

7 0
2 years ago
Solve 3x +5 =14 please help me
alisha [4.7K]
3x=14-5
3x=14-5
3x=9
x=9 ➗ 3
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3 years ago
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Whats is the sum (2/5x + 5/8) + (1/5x - 1/4)?
Leviafan [203]
<span>Whats is the sum (2/5x + 5/8) + (1/5x - 1/4)?
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B.3/5x + 3/8
C.3/5x + 5/8
D.3/5x + 7/8

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5 0
3 years ago
Use a normal approximation to find the probability of the indicated number of voters. In this case, assume that 104 eligible vot
crimeas [40]

Answer:

The probability that exactly 27 of 104 eligible voters voted is​ 0.057 = 5.7%.

Step-by-step explanation:

Binomial probability distribution

Probability of exactly x sucesses on n repeated trials, with p probability.

Can be approximated to a normal distribution, using the expected value and the standard deviation.

The expected value of the binomial distribution is:

E(X) = np

The standard deviation of the binomial distribution is:

\sqrt{V(X)} = \sqrt{np(1-p)}

Normal probability distribution

Problems of normally distributed distributions can be solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

When we are approximating a binomial distribution to a normal one, we have that \mu = E(X), \sigma = \sqrt{V(X)}.

In this case, assume that 104 eligible voters aged 18-24 are randomly selected.

This means that n = 104.

Suppose a previous study showed that among eligible voters aged 18-24, 22% of them voted.

This means that p = 0.22

Mean and standard deviation:

\mu = 104*0.22 = 22.88

\sigma = \sqrt{104*0.22*0.78} = 4.2245

Probability that exactly 27 voted

By continuity continuity, 27 consists of values between 26.5 and 27.5, which means that this probability is the p-value of Z when X = 27.5 subtracted by the p-value of Z when X = 26.5.

X = 27.5

Z = \frac{X - \mu}{\sigma}

Z = \frac{27.5 - 22.88}{4.2245}

Z = 1.09

Z = 1.09 has a p-value of 0.8621

X = 26.5

Z = \frac{X - \mu}{\sigma}

Z = \frac{26.5 - 22.88}{4.2245}

Z = 0.86

Z = 0.86 has a p-value of 0.8051

0.8621 - 0.8051 = 0.057

The probability that exactly 27 of 104 eligible voters voted is​ 0.057 = 5.7%.

5 0
3 years ago
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