Dmitri wants to cover the top and sides of this box with glass tiles that are 1 cm square. How many tiles will he need? Dmitri w
1 answer:
The number of tiles needed to cover the surface area of the box excluding the bottom is: 1,046 tiles.
<h3>What is the Surface Area of a Box?</h3>The surface area of a box is the area surrounding all its faces. A box has 6 rectangular faces. Therefore, the total surface area of the box equals the sum of all 6 rectangular faces.
<h3>What is the Surface Area of a Box?</h3>SA = 2(lw + lh + hw), where:
- l = length
- w = width
- h = height of the box
The image attached below shows the box Dmitri wants to cover. Since the bottom of the box would be excluded, therefore:
The surface area to be covered = surface area of the box - area of the bottom rectangular face
The surface area to be covered = 2(lw + lh + hw) - (l)(w)
l = 26
w = 15
h = 8
Substitute
The surface area to be covered = 2(l×w + lh + hw) - (l)(w) = 2·(15·26+8·26+8·15) - (26)(15) =
The surface area to be covered = 1436 - 390 = 1,046 cm
Area of one tile = 1 cm square
Number of tiles needed = 1,046/1
Number of tiles needed = 1,046 tiles.
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Answer:
Therefore the circumference of the circle is
Step-by-step explanation:
Let the side of the square be s
and the radius of the circle be r
The perimeter of the square is = 4s
The circumference of the circle is =2πr
Given that the length of the wire is 20 cm.
According to the problem,
4s + 2πr =20
⇒2s+πr =10
The area of the circle is = πr²
The area of the square is = s²
A represent the total area of the square and circle.
A=πr²+s²
Putting the value of s
For maximum or minimum
Differentiating with respect to r
Again differentiating with respect to r
> 0
For maximum or minimum
Therefore at , A is minimum.
Therefore the circumference of the circle is