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Vika [28.1K]
3 years ago
15

Which expression is equivalent to z to the fifth power

Mathematics
2 answers:
Svetlanka [38]3 years ago
5 0
Z • z^4
have a nice day!
Ugo [173]3 years ago
5 0

Answer:

B

Step-by-step explanation:

5×z= 5z

z×z^4 = z^5 because when the base is the same (z) and they are being multiplied together, you can add the exponents

4z×1z= 4z^2. because 4×1=4 and z×z=z^2

z^2 × y^2 = z^2 y^2 because the bases are not the same so you can not add the exponents

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Kai calculates that he spends 15% of the school day in science class. If he spends 42 minutes in science class, how many minutes
MissTica
You need to first multiply 100 by 42 then divide by 15

6 0
3 years ago
Find the area of the other polygon area=__ft
Colt1911 [192]

Answer:

108ft^2

Step-by-step explanation:

since you going up in value, you mulitple 3*9 to get 27. that means you have to multiple the other value of the bigger rectangle by 2. therefore 6*18=108

3 0
3 years ago
Consider randomly selecting a student at a large university, and let A be the event that the selected student has a Visa card an
ziro4ka [17]

Answer:

1) is not possible

2) P(A∪B) = 0.7

3) 1- P(A∪B) =0.3

4) a) C=A∩B' and P(C)= 0.3

b)  P(D)= 0.4

Step-by-step explanation:

1) since the intersection of 2 events cannot be bigger than the smaller event then is not possible that P(A∩B)=0.5 since P(B)=0.4  . Thus the maximum possible value of P(A∩B) is 0.4

2) denoting A= getting Visa card , B= getting MasterCard the probability of getting one of the types of cards is given by

P(A∪B)= P(A)+P(B) - P(A∩B) = 0.6+0.4-0.3 = 0.7

P(A∪B) = 0.7

3) the probability that a student has neither type of card is 1- P(A∪B) = 1-0.7 = 0.3

4) the event C that the selected student has a visa card but not a MasterCard is given by  C=A∩B'  , where B' is the complement of B. Then

P(C)= P(A∩B') = P(A) - P(A∩B) = 0.6 - 0.3 = 0.3

the probability for the event D=a student has exactly one of the cards is

P(D)= P(A∩B') + P(A'∩B) = P(A∪B) - P(A∩B) = 0.7 - 0.3 = 0.4

3 0
3 years ago
How would I solve for the parabolic equation with these two given points. Please answer ASAP!!
monitta
So

y=ax^2+bx+c
(x,y)
sub the points and solve

(4.28,6.48)
6.48=a(4.28)^2+b(4.28)+c

(12.61,15.04)
15.04=a(12.61)^2+b(12.61)+c
well, for 3 variables, we need equations and therefor 3 points

maybe we are supposed to assume it starts at (0,0)
so then
0=a(0)^2+b(0)+c
0=c
so then
6.48=a(4.28)^2+b(4.28)
15.04=a(12.61)^2+b(12.61)

solve for a by subsitution
first equation, minut a(4.28)^2 from both sides
6.48-a(4.28)^2=b(4.28)
divide both sides by 4.28
(6.48/4.28)-4.28a=b
sub that for b in other equation

15.04=a(12.61)^2+b(12.61)
15.04=a(12.61)^2+((6.48/4.28)-4.28a)(12.61)
expand
15.04 =a(12.61)^2+(81.7128/4.28)-53.9708a
minus (81.7128/4.28) both sides
15.04-(81.7128/4.28)=a(12.61)^2-53.9708a
15.04-(81.7128/4.28)=a((12.61)^2-53.9708)
(15.04-(81.7128/4.28))/(((12.61)^2-53.9708))=a
that's the exact value of a
to find b, subsitute to get
(6.48/4.28)-4.28((15.04-(81.7128/4.28))/(((12.61)^2-53.9708)))=b

if we aprox
a≈-0.038573167896199
b≈1.6791118501845
so then the equation is
y=-0.038573167896199x²+1.6791118501845x
7 0
3 years ago
What is the function f(x) = 2(x + 6), find x if f(x) = 22
lord [1]

Answer:

<h3>x = 5</h3>

Step-by-step explanation:

f(x) = 2(x + 6)

f(x) = 22

thereofre we have the equation:

2(x + 6) = 22      <em>use distributive property</em>

2x + 12 = 22     <em>subtract 12 from both sides</em>

2x = 10     <em>divide both sides by 2</em>

x = 5

3 0
3 years ago
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