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4 years ago

Please help Cant figure it out

Mathematics

1 answer:

IrinaVladis [17]4 years ago

3 0

Answer:

Step-by-step explanation:

If a number is to the power of a negative number, then it is just that number's reciprocal: e.g. y⁻ˣ = $\frac{1}{y^{x} }$

Therefore, m⁻² will be m² in the denominator, as n⁻³ will be n³ in the numerator.

That will look like $\frac{3n^{3} }{5m^{2} }$ .

So, that is C.

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Help please!!!!

Mrac [35]

Answer:

a = 2

b = 18

a/b = 1/9

Step-by-step explanation:

5 0

3 years ago

Pls help me on this question

stiv31 [10]

Answer:

I think the answer is option A

4 0

3 years ago

If f(x)=x+7 and g(x)=1/x-13, what is the domain of (f o g)(x)

astra-53 [7]

(f o g)(x) = 1/(x - 13) +7
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3 years ago

How to solve this problem?

valentinak56 [21]

Very nice handwriting but the math and English are confusing.

Let's assume we're told

$\displaystyle 45 = \sum_{i=1}^9 (x_i - 10)^2$

The subscript is important.

I think we're told the similar sum with 11 gives the smallest possible value for the sum. This is a rather cagey way of telling us 11 is the mean of the nine points. The mean is the number which minimizes the sum of squared deviations.

$\displaystyle 45 = \sum_{i=1}^9 (x_i - 10)^2 = \sum x_i^2 - 20 \sum x_i + 9(100)$

$\displaystyle \sum x_i^2= 20 \sum x_i - 900$

If 11 is the mean, the sum of the points is 9(11)=99.

$\displaystyle \sum x_i^2= 20 (99) - 900 = 1080$

Answer: 1080

6 0

3 years ago

If the mean heights of three groups of students consisting of 20,16 and 14 students are 167m, 150m and 1.40m respectively find t

Aleonysh [2.5K]

Answer:

1.54 m

Step-by-step explanation:

Given information:

Three groups of students

20 students with a height of 1.67 m
16 students with a height of 1.50 m
14 students with a height of 1.40 m

⇒ Total number of students = 20 + 16 + 14 = 50

To find the mean height of all the students, divide the sum of all the students' heights by the total number of students:

$\begin{aligned}\implies \sf mean\:height & =\dfrac{(20 \times 1.67)+(16 \times 1.50)+(14 \times 1.40)}{50}\\\\ & = \dfrac{33.4+24+19.6}{50}\\\\ & = \dfrac{77}{50}\\\\ & = 1.54\:\: \sf m\end{aligned}$

Therefore, the mean height of all the students is 1.54 m

6 0

2 years ago

Read 2 more answers