Answer:
<u>1092K</u>
Explanation:
We can use the combined gas law to answer this question:
P1V1/T1 = P2V2/T2,
where P, V and T are the Pressure, Volume, and Temperature for initial (1) and Final (2) conditions. Temperatures must be in Kelvin.
The problem states that V2 = 2V1 and P2 = 2P1.
Let's rearrange to solve for T2, which is the question:
T2 = T1(P2/P1)(V2/V1)
Note how the pressure and temperature values are written: as ratios. Enter the values:
T2 = (273K)(P2/P1)(V2/V1)
T2 = (273K)(2P1/P1)(2V1/V1) [Use the expressions for V2 and P2 from above]
T2 = (273K)(2)(2)
T2 = 1092K

60g after 3 hours, 30g after 6 hours and 15g after 9 hours
Explanation:
Weight of the radioactive sample = 120g
half life time period = 3 hours
(a) The weight of sample after 3 hours

The fraction of sample left

Mass of the sample left

<u>6</u><u>0</u><u>g</u><u> </u><u>of</u><u> </u><u>sample</u><u> </u><u>is</u><u> </u><u>left</u><u> </u><u>after</u><u> </u><u>3</u><u> </u><u>hours</u>
(b) The weight of sample after 6 hours

The fraction of the sample left

Mass of the sample left

<u>3</u><u>0</u><u>g</u><u> </u><u>of</u><u> </u><u>sample</u><u> </u><u>is</u><u> </u><u>left</u><u> </u><u>after</u><u> </u><u>6</u><u> </u><u>hours</u>
(c) The weight of sample after 9 hours

The fraction of sample left

Mass of sample left

<u>1</u><u>5</u><u>g</u><u> </u><u>of</u><u> </u><u>sample</u><u> </u><u>is</u><u> </u><u>left</u><u> </u><u>after</u><u> </u><u>9</u><u> </u><u>hours</u><u>.</u>
“If a certain metal is cooked, it will conduct electricity better”
- this is a hypothesis, since the statement is kind of vague...”certain metal”...and is written in an “if-then” format.
The amount of electric current that passes through a conductor is directly proportional to the voltage and is described as V = IR
- laws are usually scientific understanding that we’ve tested so much that we’ve come to a conclusion that can often be written out as a mathematical relationship. Hence, the “V = IR”
Electricity is the flow of electric charge in the form of electrons moving through a circuit
- this is a theory. I would give an explanation but I’m out of time.
Hope this helps
Answer:
The density of gallium would be greater than aluminium and boron.
Explanation:
Density:
Density is equal to the mass of substance divided by its volume.
Units:
SI unit of density is Kg/m3.
Other units are given below,
g/cm3, g/mL , kg/L
Formula:
D=m/v
D= density
m=mass
V=volume
Symbol:
The symbol used for density is called rho. It is represented by ρ. However letter D can also be used to represent the density.
As we move down the group densities increases because larger increase in mass occur with increase ion volume and greater sizes of elements down the group.
The boron, aluminium and gallium present in group thirteen. Boron is present in period two aluminium is present in period three and gallium is present in period four. So, atomic number of gallium is greater than boron and aluminium and it is appear as we move down the group. that's why gallium has larger size and greater value of density then boron and aluminium.
The value of density of gallium is 5.904 g/cm³.
The solubility of nitrogen gas in water is 1.90 mL/dL at 1.00 atm and 13.3 mL/dL at 7.00 atm.
We want to relate the solubility of a gas with its partial pressure.
We can do so using Henry's law.
<h3>What does Henry's law state?</h3>
Henry's law states that the amount of dissolved gas in a liquid is proportional to its partial pressure above the liquid.
C = k × P
where,
- C is the concentration of a dissolved gas.
- k is the Henry's Law constant.
- P partial pressure of the gas.
The solubility of nitrogen gas is 1.90 mL/dL of blood at 1.00 atm.
Since the solvent is basically water, we can understand that the concentration of nitrogen gas is 1.90 mL/dL at 1.00 atm.
We can use this information to calculate Henry's Law constant.
k = C/P = (1.90 mL/dL)/1.00 atm = 1.90 mL/dL.atm
We want to calculate the solubility of nitrogen gas at a pressure of 7.00 atm.
We will use Henry's law.
C = k × P = (1.90 mL/dL.atm) × 7.00 atm = 13.3 mL/dL
The solubility of nitrogen gas in water is 1.90 mL/dL at 1.00 atm and 13.3 mL/dL at 7.00 atm.
Learn more about solubility here: brainly.com/question/11963573